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Alisiya [41]
2 years ago
6

Scores on IQ tests are normally distributed, with a mean of 100 and a standard deviation of 15. What is the score such that 10 p

ercent of people taking the test achieve a higher score
Mathematics
1 answer:
Studentka2010 [4]2 years ago
3 0

Answer:

103.75 score

Step-by-step explanation:

10 % scored higher than the mean?

 50% is the mean %   so we need to look for the z score corresponding to 60 %    from z-score table   this is z-score of   .25

.25 standard deviations (which is 15)   above 100 =

    .25  * 15       +   100 = 103.75   score

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Michelle tried to solve an equation step by step. \begin{aligned} t-\dfrac35&=\dfrac45\\\\ t-\dfrac35+\dfrac35&=\dfrac45
valentinak56 [21]

Answer:

Step 2

Step-by-step explanation:

Michelle's step in trying to solve the equation is given below:

\begin{aligned} t-\dfrac35&=\dfrac45\\\\ t-\dfrac35+\dfrac35&=\dfrac45+\dfrac35&\green{\text{Step } 1}\\\\ t&=1&\blue{\text{Step } 2} \end{aligned}

Michelle made a mistake in Step 2.

The right hand side of Step 1:  \dfrac45+\dfrac35\neq 1

Rather, the correct sum is:

\dfrac45+\dfrac35=\dfrac75\\\\=1\dfrac25

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mrs. West took her class on a field trip to the museum cost of admission for the girls was $90 and the cost of admission for the
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Answer:

15 dollars

Step-by-step explanation:

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3 years ago
Kelly walks 1/5 mile to school every day. Jamie walks 1/2 as far as Kelly. How does Jamie walk to school every day?​
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Answer:1/10 a mile

Step-by-step explanation:

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3 years ago
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A number that when added to another number equals zero
FinnZ [79.3K]
-2+2=0 because on the number line -2 is two spots from 0 then when u add a positive 2 it equals 0.
3 0
3 years ago
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The end behaviour for the polynomial function h(x)=−x3+x4−2x+1 h ( x ) = - x 3 + x 4 - 2 x + 1 is: x→−[infinity], y→−[infinity]
Goryan [66]

Answer:

\text{As  } x \to \infty, y  \to \infty,$and as  x \to -\infty, y  \to \infty

Step-by-step explanation:

Given the polynomial function: h(x)=-x^3+x^4-2x+1

To examine its end behavior, we create a table of values that we can then examine.

\left|\begin{array}{c|c}x&h(x)\\--&--\\-4&329\\-3&115\\-2&29\\-1&5\\0&1\\1&-1\\2&5\\3&49\\4&185\end{array}\right|

From the table, we see a repeating pattern of positive values of h(x) with h(1)=-1 being an axis of symmetry.

Therefore, as:

x \to \infty, h(x)  \to \infty\\x \to -\infty, h(x)  \to \infty

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3 years ago
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