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3 years ago

12

bubble wrap sells in sheets, and each sheet has 1 million individual spherical bubbles, each with a diameter of 0.01 m. what is

the total volume of air contained in the bubbles of two sheets of bubble wrap? round to the nearest tenth.

2 answers:

Alla [95]3 years ago

6 0

Answer: A. 1.0

Step-by-step explanation:

i took the quiz

ss7ja [257]3 years ago

5 0

45400000 m cubed

take the diameter and plug it into the equation for volume of a sphere
V= 3/4 π r³
that gives us a very small number
5.24x10 -7

multiply that by 1 mil and you get the answer

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Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

David's money is three times Siti's money. Farid has RM 150 less than Siti. The total amount of their money is RM 2 000. How muc

mart [117]

Answer:

Siti's money = RM 430

David = RM 1,290

Farid = RM 280

Step-by-step explanation:

Let

Siti's money = x

David = 3x

Farid = x - 150

Total of their money = RM 2 000

x + 3x + (x - 150) = 2000

4x + x - 150 = 2000

5x = 2000 + 150

5x = 2,150

x = 2,150/5

x = RM 430

Siti's money = x

= RM 430

David = 3x

= 3(430)

= RM 1,290

Farid = x - 150

= 430 - 150

= RM 280

3 0

3 years ago

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tekilochka [14]

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mestny [16]

Marco spent more than $23. M > 23

We know the Kareem spent 8 less than Marco and that Kareem spent more than 15. If we add 8 onto the 15, we know that Marco has to be more than 23.

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3 years ago

Marc thinks a hexagon has five sides and 5 angles. Is Marc correct

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