To find the gradient of the tangent, we must first differentiate the function.
The gradient at x = 0 is given by evaluating f'(0).
The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so
Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).
So the point (0, -1) lies on the tangent. Substituting into the tangent equation:
5w^2 = A
You would multiply the width (w) by 5 because it's 5 times more than twice it's width. Then w (Width) would be to the power of 2 because it's 5 times more than twice its width. And this will all equal the Area (a)
h = 9.2 cm
Solution:
Base of smaller triangle = 5 cm
Height of smaller triangle = 2.3 cm
Base of larger triangle = 15 cm + 5 cm = 20 cm
Height of larger triangle = h
Multiply by 20 on both sides.
9.2 = h
So that Ryan should have add 15 and 5 to get a denominator of 20 on the right sides of the first line. Doing so gives the correct value, h = 9.2 cm.
We can't find the numerical term for m but in terms of p it is possible.
230 = 4p + m
m = 230 - 4p
Hope this helps!
2(x+3)=7(3x-2)
2x+6=21x-14
