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Mariulka [41]
3 years ago
13

What is the slope intercept form of the equation Y -7 equals -5 / 2 (x + 4 )

Mathematics
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

y=-5/7(x+4)+7

Step-by-step explanation:

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Ann took a taxi home from the airport. The taxi fare was
Zinaida [17]

Answer:

She would have traveled 21 miles, because it you multiply 2.1 by 21 you get 44.1 and then Ann gave a $5 tip so that would bring it up to $49.10.

Step-by-step explanation:


6 0
3 years ago
Which of these points, if any, is the midpoint of FJ?
ivanzaharov [21]

The mid-point of FJ is the number right in the middle of FJ. Find the mean of F & J. Add regardless of sign

4 + 6 = 10

10/2 = 5

Add 5 to -4

5 + -4 = 1

H is your midpoint

True. As long as AB and BC are on the same line, AB + BC = AC

hope this helps

4 0
3 years ago
An Epson inkjet printer ad advertises that the black ink cartridge will provide enough ink for an average of 245 pages. Assume t
Neko [114]

Answer:

35.2% probability that the sample mean will be 246 pages or more

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 245 \sigma = 15, n = 33, s = \frac{15}{\sqrt{33}} = 2.61

What the probability that the sample mean will be 246 pages or more?

This is 1 subtracted by the pvalue of Z when X = 246. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{246 - 245}{2.61}

Z = 0.38

Z = 0.38 has a pvalue of 0.6480.

1 - 0.6480 = 0.3520

35.2% probability that the sample mean will be 246 pages or more

4 0
3 years ago
Find the AOS for y = x^2 – 2x – 15
aivan3 [116]

Answer:

Step-by-step explanation:

x=1

6 0
3 years ago
Graph the system of equations. somebody please help
Brums [2.3K]
More or less is this

8 0
3 years ago
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