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2 years ago

14

Dan puts $11 of his allowance in his savings account every week.how many money will he have after 15 weeks

1 answer:

Fittoniya [83]2 years ago

5 0

If you multiply 11 by 15 which is 165 you will get your answer 165$

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aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

$19x^2y-4xy^2+5xy^2-16x^2y=\\3x^2y+xy^2=\\xy*(3x+y)$

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1 year ago

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Cyprian was playing football, and on 4 player here is how he did. He lost 8 yards. He gained 15 yards. He gained 7 yards. He los

lord [1]

He lost 8, so he is at -8, he then gains 15 so add 15 to -8"-8 + 15 = 7

He gains 7 so now add 7 to the total: 7+ 7 = 14

He then loses 4, so now subtract 4 from the total: 14 - 4 = 10

Answer: He gained 10 yards.

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1 year ago

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2 years ago

Three friends equally share 1/2 of a pizza how much of the pizza does each friend get

erastova [34]

The answer to this problem is 1/6.

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2 years ago

Prove that the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus.

sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

All the sides of the rhombus are congruent: $|DG|\cong |GF| \cong |EF| \cong |DE|$
The diagonals are perpendicular

Using the distance formula; $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}$

$\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}$

$|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}$

$\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}$

$|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}$

$\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}$

$|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}$

$\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}$

Using the slope formula; $m=\frac{y_2-y_1}{x_2-x_1}$

The slope of EG is $m_{EG}=\frac{2c-0}{0-0}$

$\implies m_{EG}=\frac{2c}{0}$

The slope of EG is undefined hence it is a vertical line.

The slope of DF is $m_{DF}=\frac{c-c}{a+b-(-a-b)}$

$\implies m_{DF}=\frac{0}{2a+2b)}=0$

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since $|DG|\cong |GF| \cong |EF| \cong |DE|$ and $DF \perp FG$ , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is $m_{DE}=\frac{2c-c}{0-(-a-b)}$

$m_{DE}=\frac{c}{a+b)}$

The slope of FG is $m_{FG}=\frac{c-0}{a+b-0}$

$\implies m_{FG}=\frac{c}{a+b}$

5 0

3 years ago