Find two numbers with a sum of 20 and a difference of 14
Make two equations
X+Y=20
X-Y=14
Now add x since y cancels out and add 20+14 To end up with
2x=34
Now divide 2 both sides to get x alone
2x/2=34/2
X=17
Now substitute x answer to first equation and solve for y
17+y=20
Subtract 17 both sides
Y= 3
Your two numbers are
3 and 17
= 6.25%
= 0.0625
= 625/10000
= 1/16
1.) - sqrt. 2 (which, in decimal, is about -1.4142…) , 0, sqrt. 5 (which, in decimal, is about 2.2360…) , 13/4
2.) -1.5, 3/4 (which, in decimal, is 0.75) , 3, sqrt 10 (which, in decimal, is about 3.1622…)
3.) -3/2 (which, in decimal, is -1.5), -3/7 (which, in decimal, is about -0.4285…) , 0.75, 2
Answer:
A and B
Step-by-step explanation:
You can take a look at a unit circle to find the solution to this problem (see below).
Hope this helps!
In 6,289,002 the 6 is located in the millions place and 2 is next to it. Since 2 isn't bigger than 5, the 6 stays the same and the rest of the numbers to the right turn to zeros. So, 6,289,002 rounded to the nearest million is 6,000,000.
