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Greeley [361]
3 years ago
13

Given the cost function, C(x), and the revenue function, R(x), find the number of units x that must be sold to break even.

Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0

The number of units of x that must be sold to break even is 12 units.

Explanation:

It is given that the cost function C(x) is given by

C(x)=9000 x+72,000

Also, the revenue function R(x) is given by

R(x)=15,000 x

The break even point can be determined by equating the cost function and the revenue function.

Thus, we have,

15,000 x=9000x+72000

Subtracting both sides by 9000x , we get,

6000x=72000

Dividing both sides by 6000 , we have,

x=12

Thus, it takes 12 units to be sold to break even.

Hence, the number of units of x that must be sold to break even is 12 units.

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John runs a computer software store. Yesterday he counted 123 people who walked by the store, 56 of whom came into the store. Of
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Answer:

a) There is a 45.53% probability that a person who walks by the store will enter the store.

b) There is a 41.07% probability that a person who walks into the store will buy something.

c) There is a 18.70% probability that a person who walks by the store will come in and buy something.

d) There is a 58.93% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

This a probability problem.

The probability formula is given by:

P = \frac{D}{T}

In which P is the probability, D is the number of desired outcomes and T is the number of total outcomes.

The problem states that:

123 people walked by the store.

56 people came into the store.

23 bought something in the store.

(a) Estimate the probability that a person who walks by the store will enter the store.

123 people walked by the store and 56 entered the store, so T = 123, D = 56.

So

P = \frac{D}{T} = \frac{56}{123} = 0.4553

There is a 45.53% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

56 people came into the store and 23 bought something, so T = 56, D = 23.

So

P = \frac{D}{T} = \frac{23}{56} = 0.4107

There is a 41.07% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

123 people walked by the store and 23 came in and bought something, so T = 123, D = 23.

So

P = \frac{D}{T} = \frac{23}{123} = 0.1870

There is a 18.70% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

Of the 56 people whom came into the store, 23 bought something. This means that 56-23 = 33 of them did not buy anything. So:

D = 33, T = 56

P = \frac{D}{T} = \frac{33}{56} = 0.5893

There is a 58.93% probability that a person who comes into the store will buy nothing.

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