The side lengths of the pool 10 ft and 45 ft.
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Given, a rectangle swimming pool is 8 feet deep.
One side of the pool is 4.5 times longer than the other.
Let the length of pool be n feet, the width will be 4.5n feet
The amount of water needed for the swimming pool is 3600 cubic ft
We have to find the dimensions of the pool. Now, we know that,
On taking square root on both sides we get,
So, the width will be 
I'm not really sure what I'm looking at... is it possible for you to take a better picture so I can look at the diagram if there is one + the rest of the steps?
Find the prices per ounce by dividing the dollars by the number of ounces:-
1.79 / 15 = 0.1193 dollars per ounce
1.49 / 12 = 0.1242 dollars per ounce
So the first one is the better buy.
Answer:
65 in and 39 in respectively
Step-by-step explanation:
Let r be the common ratio; when we multiply both L and R by this common ratio, we'll get the actual length and actual width of the rectangle, Recalling that the formula for the perimeter of a rectangle is P = 2L + 2R, we get:
2(5r) + 2(3r) = 16r = 208 in
Then r = 208/16 = 13
Thus, the actual length is 5(13 in) and the actual width is 3(13 in.),
or 65 in and 39 in respectively.
As a check, calculate 65 in / 39 in; this comes out to 5:3, as required.
Then
Answer:
66.9 degrees
Step-by-step explanation:
The Law of Sines states that a/sinA = c/sinC. Plugging in the values for c, a, and M < A, we get:
71/sin40 = 102/sinC
Cross multiplying, we get:
102(sin40deg) = 71(sinC)
Now, we simplify the left side and get:
65.56 = 71(sinC)
Next, we divide 65.56 by 71 to get:
0.92 = sinC
Taking the inverse sign we get:
C = 66.9 degrees
