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2 years ago

What is 399713 rounded to the Place value of the underlined digit

Mathematics

helpmeonmath

2 years ago

i cant see the under lined digit

2 answers:

meriva2 years ago

6 0

What is the underlined digit?

Rudik [331]2 years ago

4 0

What's the underlined digit???

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I need help on Part B and C on question 2

kap26 [50]

Answer:

The answer to your question is

Part A. Archimedes grades 6 1/4 tests per day

Part B. 8 19/32 days

Part C. 6 26/29 days

Step-by-step explanation:

Part A

Total time = 6 2/5 days

Number of tests = 40 tests

Process

1.- Convert the mixed fraction to improper fraction

6 2/5 = (30 + 2) / 5 = 32/5

2.- Divide 40 by 32/5

40/1 / 32/5 = (40 x 5) / (32 x 1)

= 200 / 32

Simplify

100 / 16 = 50/8 = 25/4

3.- Convert 25/4 to mixed fractions

4 25

25/4 = 6 1/4

Archimedes grade 6 1/4 tests per day

Part B

15 more tests

Total time = 32/5

Total tests = 40 + 15 = 55

Process

1.- Divide 55 by 32/5

55 / 1 / 32 /5 = (55 x 5) / (32 x 1)

= 275 / 32

2.- Convert 275/32 to a mixed fraction

32 275

256

Result 8 19/32 days

Part C

1.- Divide 55 by 7.25

50 / 7.25 = 5000 / 725

725 5000

- 4350

650

Result 6 650/750 = 6 26/29

3 0

3 years ago

Ingrid spends $120 on car repairs. Which integer represents the amount of money Ingrid must earn in order to create a zero pair?

Julli [10]

Answer: -120

Step-by-step explanation:

this would be the answer because if you take a positive and add it to a negative you get zero if their the additive inverse of the number.

8 0

2 years ago

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How do u write 25,678 in number name

egoroff_w [7]

Answer:

twenty-five thousand, six hundred seventy-eight

Step-by-step explanation:

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3 years ago

A regular octagon has a radius of 6 ft and a side length of 4.6 ft. what is the approximate area of the octagon? 71 ft2 101 ft2

Zielflug [23.3K]

The answer is 101 ft^2

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3 years ago

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The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

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\\
\\\frac{dy}{dx}2y + \frac{d}{dx}(xy+1)\ *3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
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\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
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\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
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\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
\\
\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
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\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
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\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
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\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
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3 years ago