We can use rise over run to determine the slope is 5/8. Using this slope and the point (5,2) we can write the equation: y-2 = 5/8 (x-5)
Decimal form of 5/8 is .625 , so it could be written y-2 = .625*(x-5)
The probability of occurrence for the events A, B and C is; 1/4.
<h3>What is the probability of occurrence of.the described events?</h3>
For the first event A in which case, there's no odd number on the first two rolls, the possible events are; EEE and EEO. Consequently, the required probability is;
Event A = 2/8 = 1/4.
For the event B in which case, there's an even number on both the first and last rolls; the possible events are; EEE and EOE. Consequently, the required probability is;
Event B = 2/8 = 1/4.
For the event C in which case, there's an odd number on each of the first two rolls; the possible events are; OOO and OOE. Consequently, the required probability is;
Event C = 2/8 = 1/4.
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Answer:
-4
Step-by-step explanation:
Find the gradient of the line segment between the points (0,2) and (-2,10).
Given data
x1= 0
x2= -2
y1= 2
y2=10
The expression for the gradient is given as
M= y2-y1/x2-x1
substitute
M= 10-2/-2-0
M= 8/-2
m= -4
Hence the gradient is -4
