The values of x in the triangles and the angles in the rhombus are illustrations of tangent ratios
- The values of x in the triangles are 21.4 units, 58 degrees and 66 degrees
- The angles in the rhombus are 44 and 46 degrees, respectively
<h3>How to determine the values of x?</h3>
<u>Triangle 1</u>
The value of x is calculated using the following tangent ratio
tan(25) = 10/x
Make x the subject
x = 10/tan(25)
Evaluate
x = 21.4
<u>Triangle 2</u>
The value of x is calculated using the following tangent ratio
tan(x) = 8/5
Evaluate the quotient
tan(x) = 1.6
Take the arc tan of both sides
x = arctan(1.6)
Evaluate
x = 58
<u>Triangle 3</u>
The value of x is calculated using the following tangent ratio
tan(x) = 0.34/0.15
Evaluate the quotient
tan(x) = 2.27
Take the arc tan of both sides
x = arctan(2.27)
Evaluate
x = 66
<h3>How to calculate the angles of the rhombus?</h3>
The lengths of the diagonals are:
L1 = 2 in
L2 = 5 in
Represent the angles with x and y.
The measures of the angles are calculated using the following tangent ratios
tan(0.5x) = 2/5 and y = 90 - x
Evaluate the quotient
tan(0.5x) = 0.4
Take the arc tan of both sides
0.5x = arctan(0.4)
Evaluate
0.5x = 22
Divide by 0.5
x = 44
Recall that:
y = 90 - x
This gives
y = 90 - 44
Evaluate
y = 46
Hence, the angles in the rhombus are 44 and 46 degrees, respectively
Read more about tangent ratio at:
brainly.com/question/13347349
15
Explanation: Plug in 9 into d which gives you 24-9. Making it 15.
<u>Given</u>:
A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second.
The function 
represents the height h(in feet) of the ball after t seconds.
We need to determine the time of the ball at which it is 30 feet above the ground.
<u>Time:</u>
To determine the time that it takes for the ball to reach a height of 30 feet above the ground, let us substitute h(t) = 30, we get;
Adding both sides of the equation by 16t², we get;
Subtracting both sides of the equation by 55t, we have;
Let us solve the quadratic equation using the quadratic formula, we get;
The value of t is t = 0.6 because this denotes the time taken by the ball to reach a height of 30 feet from the ground.
Therefore, the time taken by the ball to reach a height of 30 feet above the ground is 0.6 seconds.
Answer:
V≈8.44×10-6m³
Step-by-step explanation:
Answer:
3/2
Step-by-step explanation:
21/5×5/14
105/70
divide by 5
21/14
divide both by 7
3/2
