<span> The quadratic formula says that any quadratic equation of the form ax^2 + bx + c, then
x=(-b ± √(b^2 - 4ac))/2a, and so because of the square root, theres
obviously going to be no x-intercepts if b^2 - 4ac is negative, one
x-intercept if its zero, or two if its positive. So to calculate the
discriminant, which is whether it has an intercept, no intercepts or two
intercepts is:
∆=b^2 - 4ac, where delta, the greek equivalent of D, is used to represent the discriminant.
In the above equation a=-4, b=3 and c=-2, so
∆=3^2 - 4*-4*-2=9 - 32=-23, so because the discriminant is negative, then there are no x-intercepts.
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Answer: okay wow I dunno the answer sorry bud
Step-by-step explanation:
Answer:
hey help me too lol
Step-by-step explanation:
its so importnt
Answer:
163
Step-by-step explanation:
vertical angles are congruent
If i am correct, these values should add to 360, so I do it by
140 + 110 + 62 = 312
360 - 312 = 48
So the value of the last side must equal 48.
Your answer would be x = -9. Proof:
If 9 is filled in, you would have
(3 - 5(-9))
(3 - (-45))
48
Then
48 + 140 + 110 + 62 = 360!
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