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AleksandrR [38]
3 years ago
7

Find two consecutive odd integers if twice the larger, increased by the smaller equals 37,

Mathematics
1 answer:
Alexxx [7]3 years ago
6 0

Answer:

11 and 13

Step-by-step explanation:

the first (smaller) odd integer can be called x

the second (larger) odd integer can be called x+2

2(x+2)+x = 37

<em>[simplify . . .]</em>

2x+4+x = 37

3x+4 = 37

<em>[subtract 4 from each side]</em>

3x = 33

<em>[divide each side by 3; find smaller odd integer]</em>

x = 11

<em>[add 2 to find larger odd integer]</em>

x+2 = 13

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