Answer:
<h2>
<em>y</em><em>=</em><em>-</em><em>4</em></h2>
<em>Sol</em><em>ution</em><em>,</em>
<em>X=</em><em>4</em>
<em>Now</em><em>,</em>
<em>
</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>
We need to see your selection to chose from but <em>it would look something like the following
x = number of cakes
ff = 33x</em>
The first step is to set one equation equal to x or equal to y.
Ex. y = ..... or x = .....
The next step is to substitute that equation into the second equation in place of the x (or y), whichever you set it equal to.
Ex. x + y = 3
2x + y = -1
y = -x + 3 2x + (-x + 3) = -1
x + 3 = -1
x = -4
y = -(-4) + 3 y = 7 (-4,7)
Probably not online , she’ll be online sooner or later.
Answer:
Analyzed and Sketched.
Step-by-step explanation:
We are given
.
We need to find the following to sketch the graph.
1) First derivative of y with respect to x to determine the interval where function increases and decreases.
2) Second derivative of y with respect to x to determine the interval where function is concave up and concave down.

The roots are x = -1/2 and x = 1/2 but negative one cannot be possible due to logarithmic function.
x = 1/2 is absolute maximum.

So, concavity is always down.
Here, x = 0 is vertical asymptote.
I attached the picture of sketched graph.