Answer:
<em>Just don't eat the fruitcake my manz.</em>
Step-by-step explanation:
Answer:
j(x) is shifted right by
units
Step-by-step explanation:
Given
![j(x)= 51 cos(x + \frac{\pi}{2})](https://tex.z-dn.net/?f=j%28x%29%3D%2051%20cos%28x%20%2B%20%5Cfrac%7B%5Cpi%7D%7B2%7D%29)
![k(x)= 51 cos(x - \frac{3\pi}{4})](https://tex.z-dn.net/?f=k%28x%29%3D%2051%20cos%28x%20-%20%5Cfrac%7B3%5Cpi%7D%7B4%7D%29)
Required
Determine the transformation from j(x) to k(x)
The transformation shows a horizontal shift from j(x) to k(x).
First, we need to determine the unit shifter from j(x) to k(x) as follows;
![j(x)= 51 cos(x + \frac{\pi}{2})](https://tex.z-dn.net/?f=j%28x%29%3D%2051%20cos%28x%20%2B%20%5Cfrac%7B%5Cpi%7D%7B2%7D%29)
Express
as ![\frac{5\pi}{4}-\frac{3\pi}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5%5Cpi%7D%7B4%7D-%5Cfrac%7B3%5Cpi%7D%7B4%7D)
So:
becomes
![j(x) = 51cos(x + \frac{5\pi}{4}-\frac{3\pi}{4})](https://tex.z-dn.net/?f=j%28x%29%20%3D%2051cos%28x%20%2B%20%5Cfrac%7B5%5Cpi%7D%7B4%7D-%5Cfrac%7B3%5Cpi%7D%7B4%7D%29)
Reorder
![j(x) = 51cos(x -\frac{3\pi}{4}+ \frac{5\pi}{4})](https://tex.z-dn.net/?f=j%28x%29%20%3D%2051cos%28x%20-%5Cfrac%7B3%5Cpi%7D%7B4%7D%2B%20%5Cfrac%7B5%5Cpi%7D%7B4%7D%29)
Comparing this to k(x), we have:
![k(x)= 51 cos(x - \frac{3\pi}{4})](https://tex.z-dn.net/?f=k%28x%29%3D%2051%20cos%28x%20-%20%5Cfrac%7B3%5Cpi%7D%7B4%7D%29)
In other words:
![k(x) = j(x - \frac{5\pi}{4})](https://tex.z-dn.net/?f=k%28x%29%20%3D%20j%28x%20-%20%5Cfrac%7B5%5Cpi%7D%7B4%7D%29)
<em>This implies that j(x) is shifted right by </em>
<em> units</em>
Answer:
Please check if the answer is correct or not....
Answer:
I think the answer is:
-Y = 7
-Z = 10.63
-X = 9.22
Step-by-step explanation:
Hope this helps!
:)
Answer:
a. [-3, 4]
b. (-inf, -3]
c. [4, inf)
Step-by-step explanation:
Our intervals will represent the x-values
We know that since there's an arrow pointing to the left of the line that it goes on infinitely
Same thing when the arrow is going to the right
Then we can just looking at the x-values on the graph for the intervals where it starts and stops
Hope this helps
Best of luck