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3 years ago

L. - (6x - 5) = -6x +13

Mathematics

2 answers:

zzz [600]3 years ago

7 0

Answer:

No Solution.

Step-by-step explanation:

-(6x-5)=-6x+13

-6x+5=-6x+13

-6x-(-6x)+5=13

-6x+6x+5=13

0+5=13

5=13

FrozenT [24]3 years ago

4 0

Answer:

Exact form : x=-1/3

Decimal form : x=-0.3 (line over the 3!!!)

Step-by-step explanation: Isolate the variable by divinding each side by factors that don't contain the variable.

Hope this helps you out! ☺

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Answer: 125/27 as a decimal 4.62963

Step-by-step explanation:

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4 years ago

Find the inverse laplace transform of: (2 s + 4) / (s - 3)^3

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Answer:

$e^{3t}(2t+5t^{2})$

Step-by-step explanation:

$L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=$

Using the Translation theorem to transform the s-3 to s, that means multiplying by and change s to s+3

Translation theorem: $L^{1} [F(s-a)=L^{-1}[F(s)|_{s \to s-a}\\ L^{1} [F(s-a)=e^{at} f(t)$

$L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=e^{3t} L^{-1}[\frac{2(s+3)+4}{s^{3}} ]$

Separate the fraction in a sum:

$e^{3t} L^{-1}[\frac{2s+10}{s^{3}} ]=e^{3t} L^{-1}[\frac{2s}{s^{3}}+\frac{10}{s^{3}} ]=e^{3t} (L^{-1}[\frac{2}{s^{2}}]+ L^{-1}[\frac{10}{s^{3}}])$

The formula for this is:

$L^{-1}[\frac{n!}{s^{n+1}} ]=t^{n}$

Modify the expression to match the formula.

$e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ \frac{10}{2} L^{-1}[\frac{2}{s^{2+1}}])=e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])$

Solve

$e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])=e^{3t}(2t+5t^{2} )$

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3 years ago

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Step-by-step explanation:

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3 years ago

Arrange the functions in ascending order, starting with the function that eventually has th least value and ending with the func

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Answer:

$3x,3x+8,x^{2} ,x^{2}+6,4^{x} ,4^{x}+3,$

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As, can be seen from the table that the ascending order of the functions is given by $y_{4},y_{1},y_{6},y_{3},y_{5},y_{2},$ .

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3 0

3 years ago

L. - (6x - 5) = -6x +13​

L. - (6x - 5) = -6x +13