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svlad2 [7]
4 years ago
9

How to work out what is the larger 7/8 - 8/9

Mathematics
2 answers:
seraphim [82]4 years ago
8 0
8/9 is the larger. 8/9 - 7/8 =  64 /72 - 63/72 = 1/72.
pishuonlain [190]4 years ago
3 0
[\frac{7}{8}=\frac{7\cdot9}{8\cdot9}=\frac{63}{72}\\\\\frac{8}{9}=\frac{8\cdot8}{9\cdot8}=\frac{64}{72}\\\\\frac{63}{72} < \frac{64}{72}\to\frac{7}{8} < \frac{8}{9}
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Answer:

Step-by-step explanation:

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answer is 6

7 0
3 years ago
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grigory [225]

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3 years ago
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Determine whether each of these sets is nite, countably in nite, or uncount- able. For those that are countably in nite, exhibit
ira [324]

Answer:

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Integers that are divisible by 10 are countably infinite

The set are {10, 20, 30, 40, 50, 60, 70,........

Also for the negative integers divisible by 7 or 10{.......,-49, -42, -35, -28, -21, -14, -7} or {........,-70, -60, -50, -40, -30, -20, -10} are countably infinite

Step-by-step explanation:

See the set of integers divisible by 7 or 10,

{7, 14, 21, 28, 35, 42, 49,........} Or

{10, 20, 30, 40, 50, 60, 70,.......}

Can be map one-to-one to {1,2,3,4,5,6,7,...... The set of natural numbers or positive Integers.

So also, it is applicable in negative integers divisible by 7 or 10.

Therefore, they are countably infinite

A set is uncountable if it contains so many elements that they cannot be put in one-to-one correspondence with the set of natural numbers(Positive Integers). In other words, there is no way that one can count off all elements in the set in such a way that, even though the counting will take forever, you will get to any particular element in a finite amount of time.

WHILE

A set is countable or countably finite if it contains so many elements that they CAN be put in one-to-one correspondence with the set of natural numbers(Positive Integers)

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3 years ago
Happy birdday. Ur present is 50 pts u frick
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Answer: wait it’s my birthday

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3 years ago
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Dennis_Churaev [7]
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4/7 can't be reduced any further, so that's your final answer.
4 0
4 years ago
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