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svlad2 [7]
3 years ago
9

How to work out what is the larger 7/8 - 8/9

Mathematics
2 answers:
seraphim [82]3 years ago
8 0
8/9 is the larger. 8/9 - 7/8 =  64 /72 - 63/72 = 1/72.
pishuonlain [190]3 years ago
3 0
[\frac{7}{8}=\frac{7\cdot9}{8\cdot9}=\frac{63}{72}\\\\\frac{8}{9}=\frac{8\cdot8}{9\cdot8}=\frac{64}{72}\\\\\frac{63}{72} < \frac{64}{72}\to\frac{7}{8} < \frac{8}{9}
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
olasank [31]

Answer:  a_n=2(5)^{n-2}

<u>Step-by-step explanation:</u>

The explicit rule for a geometric sequence is: a_n=a_1(r)^{n-1}\quad \text{where}\ a_1\ \text{is the first term and r is the ratio}

The information provided is: a₁ = \dfrac{2}{5}  and  r = 5

a_n=\dfrac{2}{5}(5)^{n - 1}\\\\.\quad = 2(5)^{n-2}

4 0
3 years ago
Please solve the question and give correct answer with explanation so that i can understand it​
denis-greek [22]

Answer:

  • Yes

Step-by-step explanation:

Let the speed of the car is c and speed of the plane is p.

<h3>We are given:</h3>

The speed of the plane is 7 times the speed of the car

  • p = 7c

The distance traveled is

  • d = 315 km

The time difference to travel this same distance is 3 hours.

<h3>We know that:</h3>
  • d = ts, where d- distance, t- time, s - speed

Find the time for car and plane and their difference.

<h3>Car</h3>
  • t = d/s = 315/c
<h3 /><h3>Plane</h3>
  • t = d/s = 315/p = 315/(7c) = 35/c
<h3 /><h3>The difference</h3>
  • 315/c - 45/c = 3

<u>Solve it for c:</u>

  • (315 - 45)/c = 3
  • 270/c = 3
  • c = 270/3
  • c = 90 km/h

Now find the speed of plane:

  • p = 7c = 7*90 = 630 km/h

As we see, Jenny is right

6 0
2 years ago
Elisa needs 40 shirts for a charity. One store is selling shirts for $6.95 each. Another store says that the total for al 40 shi
xxTIMURxx [149]
Well, let us figure out what the first store will cost.
40*6.95=278
Now for the second store
325*0.8=260

So the first store is $278, while the second store is $260, so Elisa should buy shirts from the second store
7 0
3 years ago
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kifflom [539]
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Take this for example

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