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4 years ago

How to work out what is the larger 7/8 - 8/9

Mathematics

2 answers:

seraphim [82]4 years ago

8 0

8/9 is the larger. 8/9 - 7/8 = 64 /72 - 63/72 = 1/72.

pishuonlain [190]4 years ago

3 0

[ $\frac{7}{8}=\frac{7\cdot9}{8\cdot9}=\frac{63}{72}\\\\\frac{8}{9}=\frac{8\cdot8}{9\cdot8}=\frac{64}{72}\\\\\frac{63}{72} < \frac{64}{72}\to\frac{7}{8} < \frac{8}{9}$

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Find the equation, f(x) = a(x-h)2 + k, for a parabola that passes through the point (1,-7) and has (2,- 4) as its vertex. What i

Anettt [7]

The coordinates of the vertex are (h,k) so we can write:-
f(x) = a(x -2)^2 - 4
now when f(x) = -7 x = 1 so:-

-7 = a(1-2)^2 - 4
-7 = a - 4
a = -3

so the vertex formula is
f(x) = -3(x - 2)^2 - 4

standard form:-

f(x) = -3(x^2 - 4x + 4) - 4
= -3x^2 + 12x - 16

5 0

3 years ago

A sports club needs to raise at least $500 by selling chocolate bars for $2.50 each. Sebastian wants to know how many chocolate

mario62 [17]

Answer:

The inequality should be written as $2.50 times c is greater than or equal to c.

Step-by-step explanation:

First, identify what you know:

1) Each chocolate bar is $2.50

2) Sebastian needs to raise at least $500

So, Sebastian needs to sell at least enough chocolate bars to hit $500. The inequality cannot be written as less than or equal to, because he can't sell less than the number of chocolate bars needed to make $500.

Automatically, I can calculate the minimum number of bars he'll need to sell.

500/2.50 = 200 chocolate bars minimum

c must equal greater than or equal to $500, for Sebastian to raise enough money! So, basically Sebastian has to sell 200 bars OR more.

Hope this helps! :)

4 0

4 years ago

Read 2 more answers

Each set of numbers below represents the lengths of three line segments. Which set represent line segments that could be connect

LenKa [72]

Answer:

B is the triangle

A and E can be thought of as triangles as well with angles 0°, 0° and 180°, but it will be just a line with 3 points. So it depends whether this is a question with multiple answers or not.

Step-by-step explanation:

Thinking Process:

We need to find a formula for a triangle that uses all the sides

Cosine rule uses all sides:

$c^2 = a^2 + b^2 -2ab(cosA)$

we can rearrage this formula and make the angle $A$ the subject:

$A = cos^{-1}(\frac{a^2+b^2-c^2}{2ab})$

now you can just put the values from each option in the question into this formula and see if it gives an answer or not.

Try A. (1,2,3)

put a = 1, b = 2, c = 3 (keep in mind that you can take 'a' 'b' and 'c' as 3,2 and 1 or any other arrangement within the option A(1,2,3). All we are doing here is checking whether the answer exists or not)

$A = cos^{-1}(\frac{1^2+2^2-3^2}{2(1)(2)})$

$A = 180$ , now graphically it seems that this is just a line with 3 points, or technically you can think of as the sides of the triangle are overlapping each other, and the angle between the sides is 0 0 and 180. It depends on whether the question is asking you to be technical or not. Since the question already stated there are 3 line segments, so we can think of it as a triangle.

Try B.(3,4,5)

$A = cos^{-1}(\frac{3^2+4^2-5^2}{2(3)(4)})$

$A = 90$ , this is a triangle (specifically, this is a right angled triangle)

Try C.(1,10,100)

$A = cos^{-1}(\frac{1^2+10^2-100^2}{2(1)(10)})$

from the calculator you'll see a 'math error', this shows that there is no answer, because $cos^{-1}$ can only accept values within -1 and 1 inclusive. Hence no such triangle exists with lengths (1,10,100).