Let point (a,b) be on a unit circle.
1 answer:
(C) sin(-r) = -a
(D) sin(r) = -a
<u>Explanation:</u>
The unit circle definition allows us to extend the domain of sine and cosine to all real numbers. The process for determining the sine/cosine of any angle θ is as follows:
Starting from (1,0) move along the unit circle in the counterclockwise direction until the angle that is formed between your position, the origin, and the positive x-axis is equal to θ.
- sin θ is equal to the y-coordinate of your point, and
- cosθ is equal to the xxx-coordinate.
In the question, sin(-r) = -a and sin(r) = -a is equal to the x-coordinate, thus they are not correct.
An image is attached for reference.
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Step-by-step explanation:
câu trả lời là trong bức ảnh trên
we will select each points and find equation of line
option-A:
points are B(5,2) and C(7,-5)
x1=5,y1=2 , x2=7 , y2=-5
Firstly, we will find slope
we can plug values
we can use point slope form of line
we can plug values
...........Answer
option-B:
points are D(11,6) and E(5,9)
x1=11,y1=6 , x2=5 , y2=9
Firstly, we will find slope
we can plug values
we can use point slope form of line
we can plug values
...........Answer
option-C:
points are F(-7,12) and G(3,-8)
x1=-7,y1=12 , x2=3 , y2=-8
Firstly, we will find slope
we can plug values
we can use point slope form of line
we can plug values
...........Answer
option-D:
points are H(4,4) and I(8,9)
x1=4,y1=4 , x2=8 , y2=9
Firstly, we will find slope
we can plug values
we can use point slope form of line
we can plug values
...........Answer
option-E:
points are J(7,2) and K(-9,8)
x1=7,y1=2 , x2=-9 , y2=8
Firstly, we will find slope
we can plug values
we can use point slope form of line
we can plug values
...........Answer
option-F:
points are L(5,-7) and M(4,-12)
x1=5,y1=-7 , x2=4 , y2=-12
Firstly, we will find slope
we can plug values
we can use point slope form of line
we can plug values
...........Answer
What your teacher wants is for you to isolate y in the given equation. In other words, get y all by itself.
To do this, you'll do two basic steps:
Step 1) Subtract 2x from both sides
Step 2) Divide both sides by 3
Let's do that and we get...
2x+3y = 1470
2x+3y-2x = 1470-2x ... apply step 1
3y = 1470-2x
3y = -2x+1470
3y/3 = (-2x+1470)/3 ... apply step 2
y = (-2x)/3 + 1470/3
y = (-2/3)x + 490
After isolating y, we get y = (-2/3)x + 490
To get this into function notation, we simply replace y with f(x) to get the final answer f(x) = (-2/3)x+490 which is the same as writing
This graph represents all of the ordered pairs (x,y) that make the original equation true. For example, the point (x,y) = (0,490) is on the line where x = 0 and y = 490. This point is when 0 sandwiches are sold and 490 wraps are sold yielding a profit of $1470. Another point on this line is (x,y) = (3,488). Now 3 sandwiches have been sold along with 488 wraps leading to the same profit of $1470. Any ordered pair point you pick on the line should lead you to the same profit.
To do this, you'll do two basic steps:
Step 1) Subtract 2x from both sides
Step 2) Divide both sides by 3
Let's do that and we get...
2x+3y = 1470
2x+3y-2x = 1470-2x ... apply step 1
3y = 1470-2x
3y = -2x+1470
3y/3 = (-2x+1470)/3 ... apply step 2
y = (-2x)/3 + 1470/3
y = (-2/3)x + 490
After isolating y, we get y = (-2/3)x + 490
To get this into function notation, we simply replace y with f(x) to get the final answer f(x) = (-2/3)x+490 which is the same as writing
This graph represents all of the ordered pairs (x,y) that make the original equation true. For example, the point (x,y) = (0,490) is on the line where x = 0 and y = 490. This point is when 0 sandwiches are sold and 490 wraps are sold yielding a profit of $1470. Another point on this line is (x,y) = (3,488). Now 3 sandwiches have been sold along with 488 wraps leading to the same profit of $1470. Any ordered pair point you pick on the line should lead you to the same profit.
Answer:, so using order of applications, it simplifies to 27+1.5+9 after multiplying and dividing, and the final answer is 37.5
Step-by-step explanation: