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FrozenT [24]
3 years ago
5

Let point (a,b) be on a unit circle.

Mathematics
1 answer:
Mama L [17]3 years ago
6 0

(C) sin(-r) = -a

(D) sin(r) = -a

<u>Explanation:</u>

The unit circle definition allows us to extend the domain of sine and cosine to all real numbers. The process for determining the sine/cosine of any angle θ is as follows:

Starting from (1,0) move along the unit circle in the counterclockwise direction until the angle that is formed between your position, the origin, and the positive x-axis is equal to θ.

  1. sin θ is equal to the y-coordinate of your point, and
  2. cosθ is equal to the xxx-coordinate.

In the question, sin(-r) = -a and sin(r) = -a is equal to the x-coordinate, thus they are not correct.

An image is attached for reference.

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Find the zeros of y = 4x2 – 12x – 16
leva [86]

Answer:

x=-1 or x=4

Step-by-step explanation:

First divide by 4 to get rid of the factor 4 at x², then you have:

x² - 3x - 4 = 0

to factor that, look for two numbers that when added, give -3, and when multiplied, give -4. This is guesswork but usually doable:

-4 + 1 = -3

-4 * 1 = -4

so -4 and +1 are our numbers.

The factorization is therefore: (x - 4)(x + 1) = 0, and the solutions are

x-4 = 0 or x+1 = 0, so x=4 or x=-1

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) Evaluate the expression 6n² – 15 when n=5 6n to the second power minus 15 = 6 ( blank) to second power minus 15
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{2x+5y=26} {3x+4y=26}
NeTakaya
2x + 5y = 26....multiply by 3
3x + 4y = 26...multiply by -2
------------------
6x + 15y = 78 (result of multiplying by 3)
-6x - 8y = - 52 (result of multiplying by -2)
-----------------add
7y = 26
y = 26/7 (or 3 5/7)

2x + 5y = 26
2x + 5(26/7) = 26
2x + 130/7 = 26
2x = 26 - 130/7
2x = 182/7 - 130/7
2x = 52/7
x = 52/7 * 1/2
x = 52/14 which reduces to 26/7 (or 1 5/7)

solution is : (26/7, 26/7)
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3 years ago
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