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Ira Lisetskai [31]
3 years ago
6

Least common multiple for 40 and 25

Mathematics
1 answer:
inessss [21]3 years ago
3 0
Least common multiple for 40 and 25 is 200
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What is the area of this trapezoid?<br><br> Enter your answer in the box.<br><br> cm2=
WITCHER [35]

Download the app Math then take a picture and it wil give u the answer.

3 0
3 years ago
2. (01.07 MC)
Elena-2011 [213]
Part A: subtract 6 from both sides
Divide by -3 on both sides
X=-3
Part B: add like terms (-2K-3k)
Add 12 to both sides
Add 5k to both sides
Divide by 5 on both sides
K=3
Part C: distribute 6 into the parentheses
Add like terms together (36-5)
Subtract 1 from both sides
Subtract 36v from both sides
Divide by -30 on both sides
-1=v

7 0
2 years ago
In a forested area, the number of trees, T can be expressed as a function of the initial number of trees planted. If the initial
Wewaii [24]
N = N    (1+0.20)^5    
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Here, that'd be 10000(1.20)^5, or 24883 trees.
7 0
2 years ago
Hi :) I need help with the question in the screenshot if anybody knows it can you plz help I will give you brainliest, thanks an
amm1812

This question is difficult to give a definite answer to because it's an approximation, but I estimate the solutions to be around x = 2.6 and x = -2.6.

When they ask for solutions of the graphed function they are asking for an approximation of where the graph intercepts the x-axis, and we can see it kind of intercepts in the middle of 2 and 3, except slightly closer to 3, which is why I estimated 2.6.

The graph also appears to be symmetrical, which means the solutions will be the same except one would be negative and one would be positive, which means the second solution would be -2.6.

I hope this helps! Let me know if you have any questions :)

6 0
2 years ago
In a geometric sequence, A1 = 0.3 and r=3.Find A12, to the nearest integer
soldi70 [24.7K]

Step-by-step explanation:

We have,

First terms of geometric sequence, a = 0.3

Common ratio, r = 3

It is required to find the 12th term of a GP. The formula of the nth term is given by :

T_n=ar^{n-1}

Here, n =12

So,

T_{12}=0.3\times 3^{12-1}\\\\T_{12}=0.3\times 3^{11}\\\\T_{12}=53144.1

or

T_{12}=53144

So, the 12th term of the GP is 53144.

8 0
3 years ago
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