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TEA [102]
3 years ago
7

An 80% confidence interval for a proportion is found to be (0.27,0.33). What

Mathematics
1 answer:
alexandr402 [8]3 years ago
5 0

Answer:

.30

Step-by-step explanation:

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What is the slope of a line perpendicular to the line whose equation is 2x-y=5 ?
mariarad [96]

Answer:

-1/2

Step-by-step explanation:

the slope of the line 2x-y=5 is 2

a perpendicular line has the negative reciprocal of the slope of the other line

hopefully this helps :)

3 0
3 years ago
Someone plz help meee
coldgirl [10]

Answer:

The second one

Step-by-step explanation:

7 0
3 years ago
Find two positive numbers whose product is 64 and whose sum is a minimum. (If both values are the same number, enter it into bot
DedPeter [7]

Answer:

X = 8, y = 8

Step-by-step explanation:

This question is an optimization problem. Two equations are going to be needed here

n = x+y

P = xy

Such that 64 = xy

When we divide through by x we get:

y = 64/x

So that n becomes:

n = x + 64/x

n = x+64x^-1

We take derivative

n' = 1-64x^-2

When n' = 0 then a min|max occurs

0 = 1-64x^-2

Such that:

64/x² = 1

Divide through by x²

64 = x²

x = √64

x = 8

Remember y = 64/x

So,

Y = 64/8

Y = 8.

X = 8, y = 8

Thank you!

3 0
2 years ago
The value of 6/√12 −√3 is <br>(A) √3 (B) -6√3 (C) 6√3 (D) 2√3
Taya2010 [7]

Answer:

(D) 2√3

Step-by-step explanation:

From the above question ,we are asked to solve for:

6/√12 −√3

In other to simplify, we would expand the numerator of 6/√12

So we have;

= [6/(√4 ×√3)] - √3

= (6/ 2 ×√3) - √3

= (6/2 × √3) - √3

= (3 ×√3) - √3

= 3√3 - √3

= 2√3

Therefore, the value of 6/√12 −√3 is

option (D) 2√3

6 0
3 years ago
Will give brainliest plz help
Dominik [7]

Answer:

\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1

Step-by-step explanation:

Given:

Center of the ellipse is, (h,k)=(-4,-3)

Minor axis length is, 2b=6

A vertex of the ellipse is at (1, -3)

Now, distance between the center and the vertex is half of the length of the major axis.

Using distance formula for (-4, -3) and (1, -3), we get:

a=\sqrt{(1+4)^2+(-3+3)^2}=5

Therefore, the value of half of major axis is, a=5. Also,

2b=6\\b=\frac{6}{2}=3

Now, equation of an ellipse with center (h,k) is given as:

\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1

Plug in h=-4,k=-3,a=5,b=3 and determine the equation.

\frac{(x-(-4))^2}{5^2}+\frac{(y-(-3))^2}{3^2}=1\\\\\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1

Therefore, the equation of the ellipse is:

\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1

6 0
2 years ago
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