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3 years ago

Evaluate the numerical expression. − 1 2 − (− 3 4 )

Mathematics

2 answers:

AnnZ [28]3 years ago

5 0

Answer:

-12 + 34= 22 is the solution

stellarik [79]3 years ago

4 0

The answer is -12+34=22

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Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

Help T-T plz (14 points)

olganol [36]

Answer:

The answer is 10.5 or 10 1/2

Step-by-step explanation:

1) A=LxW

2) the height is given but you do not have the width So Divide.

3) first turn the fraction into decimals

H= 12 1/4= 12.25

A= 128 5/8= 128.625

4) 128.625 divided by 12.25 Give you 10.5

5) you can change 10.5 into a fraction 10 1/2

hopes this helps.

8 0

2 years ago

Here are three problems. Select all problems that can be solved using division. Jada cut 4 pieces of ribbon that were equal in l

Ivenika [448]

Answer:

A and C

Step-by-step explanation:

7 0

2 years ago

Micheal solved this inequality as shown: step 1: -6(x + 3) + 10 < -2 step 2: -6x - 18 + 10 < -2 step 3: -6x - 8 < -2 st

Anastaziya [24]

<h3>Answer: addition property of inequality</h3>

================================================

Explanation:

These are the steps to focus on

step 3: -6x - 8 < -2

step 4: -6x < 6

The move from the third step to the fourth step has us adding 8 to both sides. Therefore, we use the addition property of inequality.

That property has four forms

If $a > b$ then $a + c > b+c$
If $a < b$ then $a+c < b+c$
If $a \ge b$ then $a + c \ge b+c$
If $a \le b$ then $a+c \le b+c$

It's similar to the idea of starting with a = b, then adding c to both sides to get a+c = b+c

We add the same thing to both sides to keep things balanced.

8 0

1 year ago

A rectangle has an area of 96 sq ft if the width of the yard is 4 ft less than the length, what is the perimeter in ft of the ya

Veronika [31]

The area of a rectangle is obtained through the equation,

A = L x W

The width of the yard is 4 ft less than the length and may be expressed as L - 4. Length may be solved through the following steps,

A = (L)(L-4) ; 96 = L(L - 4) ; L = 12 ft

The length and width are 12 ft and 8 ft, respectively. Perimeter may be solved through the equation,

P = 2 x (L + W)

Substituting the values of L and W

P = 2 x ( 12 ft + 8 ft) = 40 ft

Therefore, the perimeter of the yard is 40 ft.

6 0

2 years ago