The point G on AB such that the ratio of AG to GB is 3:2 is; G(4.2, 2)
How to partition a Line segment?
The formula to partition a line segment in the ratio a:b is;
(x, y) = [(bx1 + ax2)/(a + b)], [(by1 + ay2)/(a + b)]
We want to find point G on AB such that the ratio of AG to GB is 3:2.
From the graph, the coordinates of the points A and B are;
A(3, 5) and B(5, 0)
Thus, coordinates of point G that divides the line AB in the ratio of 3:2 is;
G(x, y) = [(2 * 3 + 3 * 5)/(2 + 3)], [(2 * 5 + 3 * 0)/(2 + 3)]
G(x, y) = (21/5, 10/5)
G(x, y) = (4.2, 2)
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So 51+51=102 and then 10+10+10+10=40, and 102+40=142. So they will need to take 2 buses and 4 vans.
hope I helped
Answer:
x = 24/13
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
18/13 = 3/4x
<u>Step 2: Solve for </u><em><u>x</u></em>
- Divide both sides by 3/4: x = 24/13
<u>Step 3: Check</u>
<em>Plug in x to verify it's a solution.</em>
- Substitute: 18/13 = 3/4(24/13)
- Multiply: 18/13 = 18/13
Answer:
4p'fair x+2is answer in following
Answer:
A, C, B, respectively
Step-by-step explanation:
science(density and buoyancy)