We have that
point C(-2,-4)
point A(-4,-2)
we know that
the equation of a line in the intercept form is
y=mx+b
Step 1
find slope m
m=(y2-y1)/(x2-x1)
m=(-2+4)/(-4+2)------> 2/-2-------> m=-1
Step 2
find the value of b
with m=-1 and point C(-2,-4)
-4=-1*(-2)+b--------> -4=2+b-------> b=-6
y=mx+b
y=-x-6
the answer is
y=-x-6
a) A line containing point F-DF
b) Another name for line k-BC
c) A plane containing point A-M
d) An example of three non- collinear points.-(B,A)
e) The intersection of plane M and line k-C
X^2-6x+9
use fiol then add like terms
Y=27/4x+3 ........ is the answer
Answer:
x = q-4
Step-by-step explanation:
x+4 = q
Subtract 4 from each side
x+4-4 = q-4
x = q-4
