3 years ago

Please answer this question thanks

1 answer:

6 0

${x}^{2} - x - \frac{3}{4} = 0 \\ 4{x}^{2} - 4x - 3 = 0 \\ 4 {x}^{2} - (6x - 2x) - 3 = 0 \\ (4 {x}^{2} - 6x) + (2x - 3) = 0 \\ 2x(2x - 3) + 1(2x - 3) = 0 \\ (2x + 1)(2x - 3) = 0 \\ \\ x = \frac{ - 1}{2} \: and \: \frac{3}{2}$

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