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irina1246 [14]
2 years ago
11

Please answer this question thanks

Mathematics
1 answer:
Nimfa-mama [501]2 years ago
6 0

{x}^{2}  - x -  \frac{3}{4}  = 0 \\  4{x}^{2}  - 4x - 3 = 0 \\ 4 {x}^{2}  - (6x - 2x) - 3 = 0 \\ (4 {x}^{2}  - 6x) + (2x - 3) = 0 \\ 2x(2x - 3) + 1(2x - 3) = 0 \\ (2x + 1)(2x - 3) = 0 \\  \\ x =  \frac{ - 1}{2} \:  and \:  \frac{3}{2}

Hope This Will Help You

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