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Nikolay [14]
3 years ago
13

Celeste and Dora both offer guitar lessons. Celeste charges an initial fee of $5.00, and an hourly rate of $7.25. Dora has an in

itial fee of $10.25, and an hourly rate of $6.50. At how many hours of instruction will the cost for each instructor be the same?
Which equation represents the scenario?
Mathematics
2 answers:
Rina8888 [55]3 years ago
7 0

let number of hours be x

Celeste charges an initial fee of $5.00, and an hourly rate of $7.25.

C =5+7.25x...................(1)

Dora has an initial fee of $10.25, and an hourly rate of $6.50.

D=10.25+6.50x.................(2)

if the cost is same, equating equations (1) and (2)

5+7.25x=10.25+6.50x

7.25x-6.50x=10.25-5

0.75x = 5.25

x=7

so 7 hours is the answer

Alecsey [184]3 years ago
4 0

We can see that as the number of hours increase the charge also increase

Let x be the number of hours

The function denoting the scenario for Celeste

f(x)=5+7.25x

The function denoting the scenario for Dora

g(x) = 10.25+6.5x

Now we need to know the time or number of hours x, when both the functions will give us the same value , that is f(x)=g(x)

5+7.25x=10.25+6.5x

7.25x-6.5x=10.25-5.00

0.75x=5.25

x=\frac{5.25}{0.75}

x=7

Hence at 7 hours of instruction both the instructors will get the same cost

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antiseptic1488 [7]
Hey their,

3/4 
1/4
1/12
1/36
0/60

The pattern is -1/x every 2 +x/8 

How i got this was 36/12=3
3*12=36
so 60-36=24
24x3/2+24=60
then 60/5=12

Hopethis helped


7 0
3 years ago
Which statement is true about judy's method?
aniked [119]
A. Judy made a mistake between Steps 1 and 2
To factor x^{2} - 16, you have to factor it as (x-2)(x+2)(x-4), not (x-2)(x+8), because that will leave an extra 6x because of 8x - 2x. 
3 0
3 years ago
Read 2 more answers
14.
Readme [11.4K]

The domain is t=0 to t=3.2  and range is y = 0 to 57.125 feet.

<u>What are Domain and range of a Function?</u>

  • The range of values that we are permitted to enter into our function is known as the domain of a function.
  • The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input.
  • After we enter an x value, the function outputs this sequence of values. The y values are those.
  • A function can be compared to a piece of equipment on an assembly line.
  • A few screws and nuts are located on one end of the assembly line, while a car is located on the other. The function is the device in the center. The domain is the screws and bolts that we insert into the machine. The car at the other can be thought of as the range.

Given function is : y = -16t^2 + 50t + 4

It hits the ground when y=0

0 = -16t^2 + 50t + 4

8t^2 -25t -2 = 0

t = 25/16 + (1/16)sqrt(625+64) = (25+26.25)/16 = 51.25/16 = 3.2 seconds

domain is t=0 to t=3.2  [3.2]

take the derivative and set it equal to zero to find maximum height

-32t +50 = 0

t = 50/32 = 25/16 = 1.5625 seconds

-16(25/16) + 50(25/16) + 4 = 34(25/16) + 64/16 = (17(25)+32)/8 = 57.125 = maximum height

range is y = 0 to 57.125 feet.   the discus goes from 4 feet to 57 1/8 feet and back down to 0 feet.

Know more about Domain and Range with the help of the given link:

brainly.com/question/20349151

#SPJ4

8 0
2 years ago
1. Draw an appropriate Venn diagram to depict each of the following sets. U = The set of integers. A = The set of even integers.
CaHeK987 [17]

The attached diagram represents the Venn diagram of the sets

<h3>How to draw the Venn diagram?</h3>

The sets are given as:

  • The universal set, U = The set of integers.
  • A = The set of even integers.
  • B = The set of odd integers.
  • C = The set of multiples of 3.
  • D= The set of prime numbers

From the above representation, we have the following highlights:

  • Set A and set B will not intersect, because no number can be even and odd
  • Set C and set D will intersect set A because they have common elements 6 and 2, respectively
  • Set C and set D will intersect set B because they have common elements 3 and 3, respectively

Using the above highlights, we can now draw the Venn diagram

See attachment for the Venn diagram

Read more about Venn diagram at:

brainly.com/question/4910584

#SPJ1

3 0
2 years ago
Researchers at the Centers for Disease Control and Prevention have been studying the decay pattern of a new virus with a decay r
koban [17]

The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

Step-by-step explanation:

The given is,

                     A new virus with a decay rate of 19% per hour  

                    They start with 300 viruses

Step:1

                  Formula to calculate the viruses at decay rate,

                                                  y = A(1-r)^{t}............................(1)

                 Where, y - No of viruses after given time

                             A - Viruses at initial stage

                              r - Decay rate

                              t - No. of hours

                 From the given,

                              A = 300

                               r = 19% per hour

                               t = 7 hours

                Equation (1) becomes,

                                            y = 300(1-0.19)^{7}

                                               = 300(0.81)^{7}

                                               = 300(0.228767)

                                               = 68.63

               Viruses of 7 hours ≅ 69 viruses

                                                     ( or )

Step:1

        For 1st hour,

          = (No.of viruses in hour) - (No,of viruses in last hour × Decay rate )

              = (300)-(300 × 0.19)

              = 300 - 57

              = 243

       For 2nd hour,

              = (243)-(243 × 0.19)

              = 243 - 46.17

              = 196.83

      For 3rd hour,

              = (196.83)-(196.83 × 0.19)

              = 196.83 - 37.39

              = 159.4323

       For 4th hour,

              = (159.4323)-(159.4323 × 0.19)

              = 159.4323 - 30.2921

              = 129.1402

      For 5th hour,

              = (129.1402)-(129.1402 × 0.19)

              = 129.1402 - 24.5366

              = 104.6035

     For 6th hour,

              = ( 104.6035)-( 104.6035 × 0.19)

              =  104.6035 - 19.8747

              = 84.7288

     For 7th hour,

              = (84.7288)-(84.7288 × 0.19)

              =  84.7288 - 16.0984

              = 68.63 viruses

Result:

          The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

7 0
3 years ago
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