The other information that will prove that the two triangles are similar is Angle I is congruent to Angle L
<h3>How to determine the other information that will prove that the two triangles are similar?</h3>
The similar triangles are given as:
Triangle GHI and Triangle JKL
The above means that
Angle G = Angle J
Angle H = Angle K
Angle I = Angle L
The postulate is given as AA similarity postulate, and the congruent angles are given as:
Angle H = Angle K
This means that the other information that will prove that the two triangles are similar is Angle I is congruent to Angle L
Read more about AA postulate at:
brainly.com/question/21247688
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Answer:
1 -> D
2 -> C
3. -> F
4. -> E
5. -> A
6. -> B
Step-by-step explanation:
Match each function formula with the corresponding transformation of the parent function y = (x - 1)∧2
1. y = ( x - 1) 2 - 3 A. Reflected over the y-axis
2. y = - ( x - 1) 2 B. Translated up by 1 unit
3. y = ( x + 3) 2 C. Reflected over the x-axis
4. y = ( x - 2) 2 D. Translated down by 3 units
5. y = ( x + 1) 2 E. Translated right by 1 unit
6. y = ( x - 1) 2 + 1 F. Translated left by 4 units
Using the standard transformation rules
f(x) -> a*g(bx-h) + k, we can obtain the following results
Answers:
1 -> D
2 -> C
3. -> F
4. -> E
5. -> A
6. -> B
The last one x^4.
A: If you bring 2^-5 to the numerator which is what the - expects you to do, then you get x^5 which is 32
B: No problem here. 32 = 32
C: 2^1 * 2^4 = 2^(1 + 4) = 2^5.
C: 2^5 is 32
D: 2^4 = 16.
Answer: D does not agree with the others.
Answer:
yes
Step-by-step explanation:
There are several ways to go at this.
My first choice is to use a graphing calculator. It shows the function has a zero at x=5, so x-5 is a factor.
Another good choice is to use synthetic division (2nd attachment). If the remainder is zero, then x-5 is a factor. It is and it is.
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You can also evaluate the function at x=5. The remainder theorem tells you that if the value is zero, then x-5 is a factor. Evaluating the polynomial written in Horner form is a lot like synthetic division.
(((x -4)x -15)x +58)x -40 for x=5 is ... (-10·5 +58)5 -40 = 40-40 = 0
The value of h(5) is zero, so x-5 is a factor of h(x).
