Y > 2x - 3
3y - x ≤ 6
↓
y = 2x - 3
3y - x = 6
3(2x - 3) - x = 6
3(2x) - 3(3) - x = 6
6x - 9 - x = 6
6x - x - 9 = 6
5x - 9 = 6
<u> + 9 + 9</u>
<u>5x</u> = <u>15</u>
5 5
x = 3
y = 2x - 3
y = 2(3) - 3
y = 6 - 3
y = 3
(x, y) = (3, 3)
4x²+4x-35=0
factor: (2x+7)(2x-5)=0
2x+7=0, or 2x-5=0
2x=-7 or 2x=5
x=-3.5 or x=2.5
I don't see any rounding necessary in this case.
when you factor ax²+bx+c, you take the two factors of a and the two factors of c, one factor of a times one factor of c, the other factor of a times the other factors, the sum of the two products make b.
in this case, the factors of 4 is 2 and 2, the factors of -35 is -5 and 7. I line them up in the following way:
2 -5
2 7
then I multiple them diagonally, the top left 2 multiplying the bottom right 7=14, and the other 2 multiplying -5=-10, 14 and -10 make a sum of 4.
if you don't get the desired sum, switch the factors up and down till you have the right combination. Note: Do not switch left and right.
I hope this makes sense to you.
Answer:
10?
Step-by-step explanation:
Answer:
2/3
Step-by-step explanation:
2 - 1 1/3 = 2/3
