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weeeeeb [17]
3 years ago
7

Can someone help write the ratios for sin x,cos x and tan x

Mathematics
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

For the right triangle

sinx = \frac{opposite}{hypotenuse} = \frac{4\sqrt{5} }{12} = \frac{\sqrt{5} }{3}

cosx = \frac{adjacent}{hypotenuse} = \frac{8}{12} = \frac{2}{3}

tanx = \frac{opposite}{adjacent} = \frac{4\sqrt{5} }{8} = \frac{\sqrt{5} }{2}


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