Question

Can someone help write the ratios for sin x,cos x and tan x

Answer 1

Answer:

see explanation

Step-by-step explanation:

For the right triangle

sinx = $\frac{opposite}{hypotenuse}$ = $\frac{4\sqrt{5} }{12}$ = $\frac{\sqrt{5} }{3}$

cosx = $\frac{adjacent}{hypotenuse}$ = $\frac{8}{12}$ = $\frac{2}{3}$

tanx = $\frac{opposite}{adjacent}$ = $\frac{4\sqrt{5} }{8}$ = $\frac{\sqrt{5} }{2}$