Answer:
Step-by-step explanation:
B(2,10); D(6,2)
Midpoint(x1+x2/2, y1+y2/2) = M ( 2+6/2, 10+2/2) = M(8/2, 12/2) = M(4,6)
Rhombus all sides are equal.
AB = BC = CD =AD
distance = √(x2-x1)² + (y2- y1)²
As A lies on x-axis, it y-co ordinate = 0; Let its x-co ordinate be x
A(X,0)
AB = AD
√(2-x)² + (10-0)² = √(6-x)² + (2-0)²
√(2-x)² + (10)² = √(6-x)² + (2)²
√x² -4x +4 + 100 = √x²-12x+36 + 4
√x² -4x + 104 = √x²-12x+40
square both sides,
x² -4x + 104 = x²-12x+40
x² -4x - x²+ 12x = 40 - 104
8x = -64
x = -64/8
x = -8
A(-8,0)
Let C(a,b)
M is AC midpoint
(-8+a/2, 0 + b/2) = M(4,6)
(-8+a/2, b/2) = M(4,6)
Comparing;
-8+a/2 = 4 ; b/2 = 6
-8+a = 4*2 ; b = 6*2
-8+a = 8 ; b = 12
a = 8 +8
a = 16
Hence, C(16,12)
3(x-8)=12
I got this equation since there are three of the "x-8" sections that add up to the twelve length bar above
Answer:
7868
Step-by-step explanation:
⇒ This can be written algebraically (with a variable <em>x</em>) as:
562 ÷ x = 14
⇒ Convert the division as a fraction:
= 14
⇒ Multiply both sides by 562 to get rid of the fraction and to isolate the variable <em>x</em>:
562 · = 14 · 562
⇒ Simplify:
x = 7868
<u>Answer:</u> 7868
<em></em>
<em>Hope this helps!</em> :)
Answer:
4,400,073
Step-by-step explanation:
Ez
I'm guessing the question is meant to be "<span>If the radius of a circle with a area of 5.3 mm squared is multiplied by 5, what will the new area be?", so i'll answer that.
Area of a circle =</span>πr^2
5.3=πr^2, 5.3=π(5r)^2
132.5=25πr^2
