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Vanyuwa [196]
3 years ago
14

I’d appreciate itttttttt soooo muchhh if you even do only one, it’s easy but I’m tiredddddd

Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

Answer:

1. x= -1/3

2. y= -4, x= 2

3. y=-2, x=1

Step-by-step explanation:

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This question is confusing. Please help me!
velikii [3]

Answer:

x = 18

Step-by-step explanation:

Given:

  • a = 2x +3
  • b = 4x - 7

Finding x for which 3b = 5a:

  • 3b = 5a
  • 3(4x - 7) = 5(2x + 3)
  • 12x - 21 = 10x + 15
  • 12x - 10x = 15 + 21
  • 2x = 36
  • x = 36/2
  • x = 18
7 0
3 years ago
Read 2 more answers
3. The sum of the two consecutive integers is 9. What are the numbers?
lianna [129]

Answer:

option C 4&5

Step-by-step explanation:

From the word consecutive, it means the two number follow each other

Hence from the given options, we can see that only option C which has 4and 5 will add up to 9 and is consecutive

Hence the answer is option C 4&5

4 0
3 years ago
Help with distance formula
Anna35 [415]
Length= \sqrt {(x1-x2)^2+(y1-y2)^2} \\ \\ =\sqrt {(-5-(-2))^2+(1-3)^2} \\ \\ =\sqrt {-3^2+-2^2} \\ \\ = \sqrt {13} \\ \\ = 3.61 units
5 0
3 years ago
Sally Sue had spent all day preparing for the prom. All the glitz and the glamour of the evening fell apart as she stepped out o
Nuetrik [128]

We have the function

p(t)=550(1-e^{-0.039t})

Therefore we want to determine when we have

p(t_0)=550

It means that the term

e^{-0.039t}

Must go to zero, then let's forget the rest of the function for a sec and focus only on this term

e^{-0.039t}\rightarrow0

But for which value of t? When we have a decreasing exponential, it's interesting to input values that are multiples of the exponential coefficient, if we have 0.039 in the exponential, let's define that

\alpha=\frac{1}{0.039}

The inverse of the number, but why do that? look what happens when we do t = α

e^{-0.039t}\Rightarrow e^{-0.039\alpha}\Rightarrow e^{-1}=\frac{1}{e}

And when t = 2α

e^{-0.039t}\Rightarrow e^{-0.039\cdot2\alpha}\Rightarrow e^{-2}=\frac{1}{e^2}

We can write it in terms of e only.

And we can find for which value of α we have a small value that satisfies

e^{-0.039t}\approx0

Only using powers of e

Let's write some inverse powers of e:

\begin{gathered} \frac{1}{e}=0.368 \\  \\ \frac{1}{e^2}=0.135 \\  \\ \frac{1}{e^3}=0.05 \\  \\ \frac{1}{e^4}=0.02 \\  \\ \frac{1}{e^5}=0.006 \end{gathered}

See that at t = 5α we have a small value already, then if we input p(5α) we can get

\begin{gathered} p(5\alpha)=550(1-e^{-0.039\cdot5\alpha}) \\  \\ p(5\alpha)=550(1-0.006) \\  \\ p(5\alpha)=550(1-0.006) \\  \\ p(5\alpha)=550\cdot0.994 \\  \\ p(5\alpha)\approx547 \end{gathered}

That's already very close to 550, if we want a better approximation we can use t = 8α, which will result in 549.81, which is basically 550.

Therefore, we can use t = 5α and say that 3 people are not important for our case, and say that it's basically 550, or use t = 8α and get a very close value.

In both cases, the decimal answers would be

\begin{gathered} 5\alpha=\frac{5}{0.039}=128.2\text{ minutes (good approx)} \\  \\ 8\alpha=\frac{8}{0.039}=205.13\text{ minutes (even better approx)} \end{gathered}

7 0
1 year ago
Round 8,912 to the nearest ten​
tamaranim1 [39]

Answer:

8910

Step-by-step explanation:

look at the number next to the ten ( in this case it's number 1) so to it's right we have 2. which is smaller than 5. so we just cancel it and every number to it's right. now we have 891 and we have to add a zero so it's 8910

<em>Hope</em><em> </em><em>this</em><em> </em><em>helped </em><em>and</em><em> </em><em>plz</em><em> </em><em>mark</em><em> </em><em>as</em><em> </em><em>b</em><em>r</em><em>ainliest</em><em>!</em>

<em>Luna</em><em> </em><em>G</em><em>.</em>

5 0
3 years ago
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