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3 years ago

9x 2 - 18x - 7 ÷ (3x + 1)

Mathematics

1 answer:

Harman [31]3 years ago

8 0

Answer:

The quotient is: 3x-7

The remainder is: 0

Step-by-step explanation:

We need to divide 9x^2 - 18x - 7 ÷ (3x + 1)

The Division is shown in the figure attached.

The quotient is: 3x-7

The remainder is: 0

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mart [117]

Im giving you instrutions to get the answer its simple:D
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Answer:

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Step-by-step explanation:

Given the data :

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σy = 2.77

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3 years ago

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
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sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
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\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
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c=hypotenuse\\
a=adjacent\\
b=opposite\\
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$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
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\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
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tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
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\textit{and now, let's rationalize the denominator}
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musickatia [10]

Answer:

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Step-by-step explanation:

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