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Romashka [77]
3 years ago
9

Freddy is two years old than her brother. Twelve years ago, she was twice as old as he was. How old were they? Equation

Mathematics
1 answer:
Hitman42 [59]3 years ago
8 0
F=2+b
12 years ago
f-12=2(b-12)
f=2+b
2+b-12=2(b-12)
b-10=2b-24
minus b both sides
-10=b-24
add24
14=b

14-12=2
2+2=4

freddy was 4 and brother was 2
they are now 16 and 14
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jok3333 [9.3K]

Answer:

J'(-2,5)

K'(-7,5)

M'(-3.5,2)

L'(5.5,2)

Step-by-step explanation:

Please refer to the image attached to this answer.

Trapezoid JKLM is reflected over the x-axis, what do we notice about the ordered pairs of the original figure and the ordered pairs of its reflection over the x-axis is described below.

Point J , K L and M  , when reflected over x axis , there distance from the y axis remains the same in second quadrant. the x coordinate becomes negative however  the y coordinates remains the same.

The coordinates will be as shown in the image attached.

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3 years ago
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Al sumar y/o restar números decimales, siempre se debe aplicar la norma de los signos. * 1 punto FALSO VERDADERO
Luden [163]

Answer:

La norma de los signos es para el producto de números reales, y la norma es la siguiente.

(+)*(+) = (+)

(+)*(-) = (-)

(-)*(+) = (-)

(-)*(-) = (+)

Es decir, el producto de dos números de mismo signo es siempre positivo

El producto de dos números de distinto signo es siempre negativo.

Particularmente, para la suma esta norma no funciona (pues no está definida para la suma)

Pero en casos como:

5 - (-4)  

(esto sería: "la diferencia entre cinco y menos cuatro")

notar que podemos reescribir esto como:

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Ahora podemos aplicar la norma de los signos:

5 + 4 = 9

Donde aplicamos la norma de los signos,  

Podemos concluir que, si bien es una regla que aplica al producto, siempre la tenemos que tener en cuenta en cualquier operación que hagamos.

Por lo podemos concluir que la respuesta correcta es verdadero.

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Answer:

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Step-by-step explanation:

Suitability of the normal distribution:

In a binomial distribution with parameters n and p, the normal approximation is suitable is:

np >= 5

n(1-p) >= 5

In this question, we have that:

p = 0.9

Since p > 0.5, it means that np > n(1-p). So we have that:

n(1-p) \geq 5

n(1 - 0.9) \geq 5

0.1n \geq 5

n \geq \frac{5}{0.1}

n \geq 50

The minimum sample size needed for use of the normal approximation is 50.

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Step-by-step explanation:

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Step 1 : open the bracket with -5x^4

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Hint: - * + = -

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15x^6 - 20x^5 + 10x^4

We can look for a factor that can go through as in that can divide all without a reminder

Factors of

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1 * 15

20 - 4 *5

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1 * 20

10 - 2*5

1 * 10

Since the factor of 5 is common in all, so we are using 5 to divide through

15x^6 - 20x^5 + 10x^4

Using 5 to divide through

15x^6 / 5 - 20x^5 / 5 + 10x^4 / 5

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Answer:

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