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deff fn [24]
3 years ago
13

Suppose there is a 1.2 Fahrenheit drop in temperature for every thousand feet that an airplane climbs into the sky if the temper

ature on the ground is 64.7 Fahrenheit what will the temperature be when the plane reaches an altitude of 5000 feet
Mathematics
1 answer:
Nostrana [21]3 years ago
3 0

9514 1404 393

Answer:

  58.7 °F

Step-by-step explanation:

At 5000 feet, the airplane is 5 times 1000 feet above the ground, so the temperature will have dropped 5 times 1.2 °F.

  64.7 - 5×1.2 = 64.7 -6.0 = 58.7

At 5000 feet, the temperature is 58.7 °F.

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Select all ratios equivalent to 26:15
olchik [2.2K]

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\frac{130}{75 }

is equivalent to

\frac{26}{15}

because

\frac{26 \times 5}{15 \times 5}  =  \frac{130}{75}

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Can someone help me with my Algerbraic reasoning class?
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3 years ago
Which equation represents a circle with a center at -3, -5) and a radius of 6 units?
vesna_86 [32]

Answer:

(x+3)²+(y+5)² = 36

Step-by-step explanation:

The general equation of a circle is expressed as;

(x-a)²+(y-b)² = r² where;

(a, b) is the centre of the circle

r is the radius of the circle

Given

Centre (-3, -5)

a = -3 and b = -5

radius r = 6units

Substitute

(x-a)²+(y-b)² = r²

(x-(-3))²+(y-(-5))² = 6²

(x+3)²+(y+5)² = 36

hence the required equation is (x+3)²+(y+5)² = 36

7 0
3 years ago
Find the area and perimeter of ABC at right. Give approximate (decimal) answers, not exact answers
Sever21 [200]

Answer:

Area of Δ ABC = 21.86 units square

Perimeter of Δ ABC = 24.59 units

Step-by-step explanation:

Given:

In Δ ABC

∠A=45°

∠C=30°

Height of triangle = 4 units.

To find area and perimeter of triangle we need to find the sides of the triangle.

Naming the end point of altitude as 'D'

Given BD\perp AC

For Δ ABD

Since its a right triangle with one angle 45°, it means it is a special 45-45-90 triangle.

The sides of 45-45-90 triangle is given as:

Leg1 =x

Leg2 =x

Hypotenuse =x\sqrt2

where x is any positive number

We are given BD(Leg 1)=4

∴ AD(Leg2)=4

∴ AB (hypotenuse) =4\sqrt2=5.66  

For Δ CBD

Since its a right triangle with one angle 30°, it means it is a special 30-60-90 triangle.

The sides of 30-60-90 triangle is given as:

Leg1(side opposite 30° angle) =x

Leg2(side opposite 60° angle) =x\sqrt3

Hypotenuse =2x

where x is any positive number

We are given BD(Leg 1)=4

∴ CD(Leg2) =4\sqrt3=6.93

∴ BC (hypotenuse) =2\times 4=8  

Length of side AC is given as sum of segments AD and CD

AC=AD+CD=4+6.93=10.93

Perimeter of Δ ABC= Sum of sides of triangle

⇒ AB+BC+AC

⇒ 5.66+8+10.93

⇒ 24.59 units

Area of Δ ABC = \frac{1}{2}\times base\times height

⇒  \frac{1}{2}\times 10.93\times 4

⇒ 21.86 units square

5 0
3 years ago
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