To make it useable, the disk first needs to be subdivided into logical volumes, then formate, so that it is readable by the systems.
Add the following constants in the class definition, before the main method:
private final static float START_COST = 1.5f;
private final static float HIGH_TARIFF = 0.5f;
private final static float LOW_TARIFF = 0.25f;
private final static int FIXED_MINS = 2;
private final static int HIGH_TARIFF_MINS = 10;
Then add this to the main method you already had:
float price = START_COST;
if (x > FIXED_MINS) {
if (x <= HIGH_TARIFF_MINS) {
price += HIGH_TARIFF*(x-FIXED_MINS);
}
else {
price += HIGH_TARIFF*(HIGH_TARIFF_MINS-FIXED_MINS)
+ LOW_TARIFF*(x-HIGH_TARIFF_MINS);
}
}
System.out.printf("A %d minute call costs %.2f", x, price);
Answer:
make sure the speaker is clean and you volume setting is on normal there is alot of setting for deaf people so make sure that is correctly
Answer:
The VI in LabView indicates c-Virtual Instrument
Explanation:
The VI in LabView is a program-subroutine. The VI stands for Virtual Instrument. The VI is composed of a Block diagram, Connector panel and a Front Panel.
Answer:
A. Fetch.
Explanation:
The fetch-decode-execute process of simply the fetch-execute process of the CPU are stages the CPU follow to process information and the switch state or shutdown.
The stages of this process is implied in its name, that is, the stages are fetch, decide and execute.
The fetch stage retrieves the next instruction from the memory.
The decode stage converts the clear text instruction set to electronic signals and transfer it to the appropriate registers.
The execute stage is the action carried out in the arithmetic logic unit.
