Answer:
nTag
Explanation:
nTag describe -Providing information on freight limitations-Preparing documentation-Packing exhibit materials-Helping to ensure that shipments arrive on time.
Answer:
Check the explanation
Explanation:
An integer (int) is of two different bytes and each page has 200 bytes in length. What this means is that each row of array A (100 int) will fits perfectly in a page.
(a) For the initial or first array-initialization loop, one column is processed at a time, so a page fault will be generated at every inner loop iteration, with a total of 100*100=10,000 page faults.
(b) And when it comes to the second array-initialization loop, one row is processed at a time, and a page fault is generated at every outer loop iteration, with a total of 100 page faults.
Hence second array-initialization loop, has better spatial locality.
Answer:
200Ω
Explanation:
In series circuits, you add the resistances.
Please provide the language you're using when you ask for programming help, otherwise you aren't going to get the answer that you are looking for.
Here it is in Java, and I'm assuming the number is given via user input? Otherwise, just remove the user input function and replace the integer with a value of your choice. Note, that this isn't the full code; only what is relevant to the question.
public static void main(String[] args) {
int num = numInput(10);
printDoubles(num, 100); // You can create a user input function for
// maxValue if you wanted to.
}
/**
* Receives user input between 0 and the absolute value of maxInput.
* @param maxInput The largest absolute value that can be input.
*/
private static int numInput(int maxInput) {
Scanner sc = new Scanner(System.in);
maxInput = Math.abs(maxInput);
int num = 0;
while (!(num > 0 && num <= maxInput)) {
num = sc.nextInt();
if (!(num > 0 && num <= maxInput)) {
System.out.println("Input too small or too large");
}
}
return num;
}
/**
* Continues to print out num doubled until maxValue is reached.
* @param num The number to be printed.
* @param maxValue The maximum value (not including in which num can be doubled to.
*/
private static void printDoubles(int num, int maxValue) {
if (num >= maxValue) {
System.out.println("No output.");
}
while (true) {
if (num >= maxValue) {
break;
}
if (num < maxValue) {
System.out.print(num + " ");
}
num *= 2;
}
System.out.println();
}
Refer to the attachment!!
