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Cerrena [4.2K]
3 years ago
15

What is the coefficient of the acid that produces AlCl3 in the reaction mixing Al(OH)3 and HCl after the equation has been balan

ced?
1

3

2

4
Chemistry
1 answer:
kramer3 years ago
3 0

Answer:

3.

Explanation:

  • Al(OH)₃ reacts with HCl to produce AlCl₃ and water according to the balanced equation:

<em>Al(OH)₃ + 3 HCl → AlCl₃ + 3H₂O,</em>

<em></em>

<em>It is clear that 1.0 mole of Al(OH)₃ reacts with 3.0 mole of HCl to produce 1.0 mole of AlCl₃ and 3.0 moles of H₂O,</em>

<em />

<em>So, the coefficient of HCl is 3.</em>

<em></em>

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V KOH = 41 mL

Explanation:

for neutralization:

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∴ V H2SO4 = 41 mL = 0.041 L

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4 0
3 years ago
What is the molarity of a solution in which 7.1 g of sodium sulfate is dissolved in enough water to make 100. mL of solution?
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Answer:

0.50 M

Explanation:

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  • Volume of solution: 100 mL

Step 1: Calculate the moles of the solute

The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:

7.1g \times \frac{1mol}{142.02g} = 0.050mol

Step 2: Convert the volume of solution to liters

We will use the relation 1 L = 1000 mL.

100mL \times \frac{1L}{1000mL} =0.100L

Step 3: Calculate the molarity of the solution

M = \frac{moles\ of\ solute }{liters\ of\ solution} = \frac{0.050mol}{0.100L} =0.50 M

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2 years ago
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