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3 years ago

I don’t understand this question.

Mathematics

1 answer:

Anastaziya [24]3 years ago

4 0

<span>In a triangle the sum of two sides is always greater than the third side.

5.6-4.0 < x < 5.6+4.0
1.6 < x < 9.6 </span>← answer

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A football field is a rectangle 48m wide and 91m long. The coach asks players to run diagonally across the field. How far did th

bagirrra123 [75]

Answer:

102.88 m

Step-by-step explanation:

Pythagorean Theorem:

a²+b²=c²

48²+91²=c²

2304+8281=10585

c²=10585

Square both sides

c= 102.88

How far the players ran:

102.88 m

4 0

3 years ago

7th grade math help me please :))

mash [69]

Answer:

8/15 = 16/30 = 24/45 = 32/60

= 40/75 = 48/90 = 56/105 = 64/120

= 72/135 = 80/150 = 88/165 = 96/180

= 104/195 = 112/210 = 120/225 = 128/240

= 136/255 = 144/270 = 152/285 = 160/300

= 168/315 = 176/330 = 184/345 = 192/360

= 200/375 = 208/390 = 216/405 = 224/420

= 232/435 = 240/450 = 248/465 = 256/480

= 264/495 = 272/510 = 280/525 = 288/540

= 296/555 = 304/570 = 312/585 = 320/600

= 328/615 = 336/630 = 344/645 = 352/660

= 360/675 = 368/690 = 376/705 = 384/720

= 392/735 = 400/750 = 408/765 = 416/780

= 424/795 = 432/810 = 440/825 = 448/840

= 456/855 = 464/870 = 472/885 = 480/900

= 488/915 = 496/930 = 504/945 = 512/960

= 520/975 = 528/990 = 536/1005 = 544/1020

= 552/1035 = 560/1050 = 568/1065 = 576/1080

= 584/1095 = 592/1110 = 600/1125 = 608/1140

= 616/1155 = 624/1170 = 632/1185 = 640/1200

= 648/1215 = 656/1230 = 664/1245 = 672/1260

= 680/1275 = 688/1290 = 696/1305 = 704/1320

= 712/1335 = 720/1350 = 728/1365 = 736/1380

= 744/1395 = 752/1410 = 760/1425 = 768/1440

= 776/1455 = 784/1470 = 792/1485 = 800/1500

Step-by-step explanation:

7 0

3 years ago

A motorcyclist travels 98 km in 1 hour 10 minutes.calculate his average speed ,giving your answer in kilometres per hour.

joja [24]

10 minutes is 1/6 of an hour.

1 hour and 10 minutes = 7/6 hours

98 km / 7/6 = 98 x 6/7 = (98 x 6) /7 = 588/7 = 84 km per hour

3 0

3 years ago

Read 2 more answers

PLEASE HELP WITH THESE TWO QUESTIONSSS 1. Which value is equivalent to sin20∘?

Nata [24]

Answer:

a) $\cos(70\degree)$

b) 12.72 units

Step-by-step explanation:

Recall that the sine and cosine are completed functions.

This means that: $\sin(x)=\cos(90-x)$

$\sin(20\degree)=\cos(90-20)$

$\sin(20\degree)=\cos(70\degree)$

Recall that: sine ratio is opposite/hypotenuse

$\sin 58=\frac{|PQ|}{15}$

This implies that:

$|PQ|=15\sin 58$

$|PQ|=15(0.848)$

$|PQ|=12.72$

4 0

3 years ago

For the function f(x) and g(x) given in the graph. Find f(g(2))

Katen [24]

Answer:

f(g(2)) = 4

Step-by-step explanation:

find g(2) then substitute the value obtained into f(x)

locate x = 2 on the x- axis, go vertically up to meet g(x) at (2, 5 )

locate x = 5 on the x- axis, go vertically up to meet f(x) at (5, 4 )

then f(g(2)) = 4

3 0

2 years ago