3 years ago

I don’t understand this question.

1 answer:

4 0

In a triangle the sum of two sides is always greater than the third side.

5.6-4.0 < x < 5.6+4.0
1.6 < x < 9.6 ← answer

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What are the x-intercepts of y=2x^2+6x-20?

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Answer:

the x-intercepts are -5 and 2

Step-by-step explanation:

$y=2x^2+6x-20$

x-intercept is when y is set equal to zero

So, y = 0

$0 = 2x^2+6x-20$

$2x^3+6x-20 = 0\\Taking \ 2 \ common\\2(x^2+3x-10) = 0\\Dividing \ both \ sides \ by \ 2\\x^2+3x-10 = 0\\Using \ mid\ term \ break \ formula\\x^2+5x-2x-10 = 0\\x(x+5)-2(x+5)=0\\Taking \ (x+5) \ common\\(x+5)(x-2) = 0$

Either,

x+5 = 0 OR x-2 = 0

x = -5 OR x = 2

So, the x-intercepts are -5 and 2

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