Question

Find the balance on a deposit of $455 that earns 4% interest compounded annually for 2 years. $36.40 $491.40 $492.13 $819

Answer 1

$A=P(1+ \frac{r}{n})^{tn}$
A=future amount
P=present amount
r=rate in decimal
n=number of times per year compounded
t=time in years

given
P=455
r=4%=0.04
n=1
t=2

$A=455(1+ \frac{0.04}{1})^{(2)(1)}$
$A=455(1+ 0.04)^{2}$
$A=455(1.04)^{2}$
A=492.128
round
$492.13
3rd option

Answer 2

The answer is $492.13
Multiply 455 x .04
Then, add that answer(18.2) to 455
Then, use that sum(473.2) and multiply it by .04
Then, add that(18.928) to to your first answer(473.2) for the final answer which is 492.128 which is rounded to $492.13