Let s be the side of the square. The length of the rectangle is 3s and its width is equal to s - 2. From the given condition,
A (square) = A (rectangle)
s² = (3s)(s - 2)
s² = 3s² - 6s
-2s² = -6s
s = 3
Thus, the length of the rectangle is 9 and its width is 1
For this case, we must build a quotient that, when multiplied by the divisor, eliminates the terms of the dividend until it reaches the remainder. In this case we have to:
Remainder: 20
Quotient: 3x-9
It must be fulfilled that:
Dividend = Quotient * Divider + Remainder
Answer:
See attached image
I assume you mean these as fractions, which in that case it is A