<h2>~<u>Solution</u> :-</h2>
Here, it is given that the bag contains 25 paise coins and 50 paise coins in which, 25 paise coins are 6 times than that of 50 paise coins. Also, the total money in the bag is Rs. 6.
- Hence, we can see that, here, we have been given the linear equation be;
Let the number of coins of 50 paise will be $ x $ and the number of coins of 25 paise will be $ 6x $ as given. . .
Hence,




- Hence, the number of 50 paise coins will be <u>2</u>. And, 6 times of two be;

- Hence, the number of 25 paise coins will be <u>12</u>.
Stop copying the question, it's confusing
so 100 cookies and 20 brownies
what is the greatest number you can divide them both by?
find the GCF
factor them
100=2*2*5*5
20=2*2*5
so the GCF is the common group to both or 2*2*5 or 20
100/20=5
20/20=1
there are 20 groups, each wit 5 cookies and 1 brownie
20 groups
Answer:
26
Step-by-step explanation:
Complementary angles add to 90 degrees
a+b = 90
64+b = 90
Subtract 64 from each side
64-64 +b = 90-64
b = 26