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grin007 [14]
4 years ago
7

What is the root of this equation? 2x^2 - 4x + 9 = 0​

Mathematics
1 answer:
faust18 [17]4 years ago
4 0

Answer:

x = 1 + i sqrt(7/2) or x = 1 - i sqrt(7/2)

Step-by-step explanation:

Solve for x:

2 x^2 - 4 x + 9 = 0

Divide both sides by 2:

x^2 - 2 x + 9/2 = 0

Subtract 9/2 from both sides:

x^2 - 2 x = -9/2

Add 1 to both sides:

x^2 - 2 x + 1 = -7/2

Write the left hand side as a square:

(x - 1)^2 = -7/2

Take the square root of both sides:

x - 1 = i sqrt(7/2) or x - 1 = -i sqrt(7/2)

Add 1 to both sides:

x = 1 + i sqrt(7/2) or x - 1 = -i sqrt(7/2)

Add 1 to both sides:

Answer:  x = 1 + i sqrt(7/2) or x = 1 - i sqrt(7/2)

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We can then rewrite the square root terms as follows:

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Next, we can use the property of square roots that says that the square root of a number is equal to the square root of each of its prime factors. This means that we can rewrite the square root term as follows:

√(3) / √(2 * 2 * 2) = √(3) / √(2) / √(2) / √(2)

Since the square root of a number is the same as the number itself, we can simplify the expression further by removing the square root symbols from the prime numbers 2:

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