Question

A Local group claims that the police issue more than 60 speeding tickets a day in thire area. To prove their point, they randomly select 2 weeks. Their yields the number of tickets issued for each day. The data are listed below. at a =0.01, test the group's claim using P- value.
70 48 41 68 69 55 70

57 60 83 32 60 72 58

the mean = 60.2

Standard D= 12.9

Answer 1

Answer:

The group's claim is not supported at 1% significance level.

Step-by-step explanation:

given that a local group claims that the police issue more than 60 speeding tickets a day in thire area

The data they collected for 2 weeks is given below:

70 48 41 68 69 55 70

57 60 83 32 60 72 58

$\bar x = 60.2\\s = 12.9\\n=14$

Std error of mean = $\frac{12.9}{\sqrt{14} } \\=3.4477$

$H_0: \bar x=60\\H_a: \bar x >60$

(Right tailed test at 1% significance level)

Mean difference = 0.10

Test statistic t with df 13 = mean difference/std error

= 0.029

p value = 0.4886

Since p >0.01, we accept null hypothesis

The group's claim is not supported at 1% significance level.