Answer:
B. The approximate length of EF is 4.47 units, and the approximate perimeter of triangle EFG is 12.94 units.
Step-by-step explanation:
First step is to determine the length of EF, since that will give us 2 sides of the triangle (since EG = EF).
From the diagram, we can easily make a rectangle triangle by dropping a vertical line from vertex E, let's name Z the meeting point of that line with the segment GF. Then we have a rectangle triangle EZF with a height of 4 and a base of 2, of which EF is the hypotenuse. So...
EF² = 4² + 2² = 16 + 4 = 20
EF = √20 = 4.47
Now that we have EF, we also have EG:
EF = 4.47
EG = 4.47
GF = 4 (visible on the graph)
Perimeter = 4.47 + 4.47 + 4 = 12.94 units.
Answer:
6 square root of 2
Step-by-step explanation:
sin theta = opposite / hypotenuse
sin 45 = 6/x
Multiply by x
x sin 45 = 6
Divide by sin 45
x sin 45/ sin 45 = 6 / sin 45
x = 6/ sin 45
x = 6/ (1/sqrt(2))
x = 6 sqrt(2)
<span>The equation is not quadratic in for because it cannot be written as a second degree polynomial</span>
C.
She said that I don’t need her 54
Answer:
C
Step-by-step explanation:
We want a line of best fit, which means we want to create a line that the data points will lie closest to.
One thing we can do is find the slope between the bottom-leftmost point and the top-rightmost point. This is because if we were to draw a line connecting these two, it will cut through the data quite well.
Those two points are (9, 15) and (16, 18), so the slope is change in y divided by the change in x:
(18 - 15) ÷ (16 - 9) = 3 ÷ 7 ≈ 0.4
Eliminate A and B.
Now we need to determine the y-intercept. This needs no calculations; simply look at the graph: there's no way a line cutting through the y-intercept point of (0, 18) will perfectly match the data points; instead it must be a y-intercept lower than 18. So, eliminate D.
The answer is C.
