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AlladinOne [14]
2 years ago
9

Deon paid bills with 1/2 of his paycheck and put 1/5 of the remainder in savings. The rest of his paycheck he divided equally am

ong the college accounts of his 3 children. What fraction of his paycheck went into each child's account?
Mathematics
1 answer:
gtnhenbr [62]2 years ago
6 0

\frac{3}{10} of his paycheck went into each child's account.

<em><u>Explanation</u></em>

Deon paid bills with \frac{1}{2} of his paycheck.

So, the remaining amount of his paycheck = 1- \frac{1}{2}= \frac{1}{2}

Now he put \frac{1}{5} of that remaining amount in savings. So, the amount put in savings =\frac{1}{2}*\frac{1}{5}=\frac{1}{10}

The <u>rest amount of his paycheck</u> will be:  1-\frac{1}{10}= \frac{9}{10}

He divided that rest amount equally among the college accounts of his 3 children.

So, the fraction of his paycheck went into each child's account = \frac{9}{10}\div 3= \frac{9}{10}\times \frac{1}{3} = \frac{3}{10}

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Triangle OPQ is similar to triangle RST. Find the measure of side RS. Round your answer to the nearest tenth if necessary. OPQR
Andrews [41]

Answer:

RS  =  75.3

Step-by-step explanation:

You need to set up the proportion of corresponding sides.

\frac{PQ}{ST}  =  \frac{PO}{RS}

\frac{7}{31}  = \frac{17}{RS}

7(RS) = 31(17)

         =  527

RS = 527/7 = 75.2857...

     =  75.3

3 0
3 years ago
1. We want to know how much money Houston people would like to spend on
MAXImum [283]
I think it’s 500 volunteers
6 0
2 years ago
2+4=what is the answer to 2 + 4
Nitella [24]
I don’t know if this is a joke or not but the answer is 6
6 0
3 years ago
4. Amazon executives believe that at least 70% of customers would return a product 2 days after it arrives at their home. A samp
inysia [295]

Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.1635 = 16.35% probability of a sample result with 68% or fewer returns prior to the third day.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportions has mean \mu = p and standard error s = \sqrt{\frac{p(1 - p)}{n}}

In this problem:

  • Sample of 500 customers, hence n = 500.
  • Amazon believes that the proportion is of 70%, hence p = 0.7

The <u>mean and the standard error</u> are given by:

\mu = p = 0.7

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.7(0.3)}{500}} = 0.0205

The probability is the <u>p-value of Z when X = 0.68</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.68 - 0.7}{0.0205}

Z = -0.98

Z = -0.98 has a p-value of 0.1635.

0.1635 = 16.35% probability of a sample result with 68% or fewer returns prior to the third day.

A similar problem is given at brainly.com/question/25735688

7 0
2 years ago
80% of 65 please help
Sonbull [250]
The answer is 52.

65 x 0.8 = 52.
5 0
2 years ago
Read 2 more answers
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