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Law Incorporation [45]
3 years ago
15

Help me plz answer it's due tomorrow ​

Mathematics
1 answer:
k0ka [10]3 years ago
4 0

Answer:

8/15

Step-by-step explanation:

multiply 2/5 by 3

6/15 + 2/15 = 8/15

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l+l+w+w= p
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Find the value of c that completes the square<br> 2 + 20r + c
Morgarella [4.7K]

Answer:

c=5

Step-by-step explanation:

5

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Round the following to the nearest hundreds. 23457,45289,2458​
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A bike path is 3 miles long. there are distance markers every path one fourth mile to the end of the path. which number line cor
Fynjy0 [20]

Given :

A bike path is 3 miles long. there are distance markers every path one fourth mile to the end of the path.

To Find :

Which number line correctly models this situation and the total number of distance markers.

Solution :

It is given that their are markers every 1/4 part of mile.

So, their are 4 markers per mile.

Numbers of markers in 3 miles long path is :

n = 3\times 4\\\\n = 12

Therefore, the total number of distance markers in 3 mile path is 12.

Hence, this is the required solution.

5 0
3 years ago
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
3 years ago
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