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neonofarm [45]
4 years ago
6

Evaluate the expression p(11,7)

Mathematics
1 answer:
LenKa [72]4 years ago
8 0
P11,p7 ?

I dont really understand what that is so.
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Solve for h<br> A=1/2(a+b)h
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The answer should be 2A/(a+b)=h

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What is the absolute value transformation of this function?
xxMikexx [17]

Answer:

k(x) = -|x + 2| + 3

Step-by-step explanation:

Parent function of the absolute function given in the graph,

f(x) = |x|

1). Function 'g' is reflected across the x-axis, then the image will be,

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2). Function 'h' the shifted 2 units left and 3 units upwards, image function will be,

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Step-by-step explanation:

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3 years ago
Which are the roots of the quadratic function f(b) = 62 – 75? Select two options.
elena55 [62]

Answer:

b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}

Step-by-step explanation:

Given

f(b) = b^2 - 75

Required

Determine the roots

To get the root of the function, then f(b) must be 0;

i.e. f(b) = 0

So, the expression becomes

0 = b^2 - 75

Add 75 to both sides

75 + 0 = b^2 - 75 + 75

75 = b^2

Take square roots of both sides

\sqrt{75} = \sqrt{b^2}

\sqrt{75} = b

Reorder

b = \sqrt{75}

Expand 75 as a product of 25 and 3

b = \sqrt{25*3}

Split the expression

b = \sqrt{25} *\sqrt{3}

b = \±5 *\sqrt{3}

b = \±5 \sqrt{3}

b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}

The options are not clear enough; however the roots of the equation are b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}

4 0
4 years ago
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