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dusya [7]
2 years ago
13

What is the value of y? ASAP please

Mathematics
2 answers:
PSYCHO15rus [73]2 years ago
6 0
The answer is option c- 68°
Andre45 [30]2 years ago
6 0
So, to answer your question, Y= C. 68<span>°.

Since the sum of a triangle's three sides has to add up to 180</span>°, I looked and checked what numbers would make the equation work. 112° is too high, and 44° and 56° were too low. 68<span>° works because 68-12 is 56, 56+56 is 112, and 112+ 68 adds up to 180.</span>
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write the equation of the line (in slope-intercept form) that passes through the points (2,3 and (5,7)
AfilCa [17]

Answer:

The answer to your question is    y = 4/3x + 1/3

Step-by-step explanation:

Data

Point A = (2, 3)

Point B = (5, 7)

Process

1.- Calculate the slope

x1 = 2    y1 = 3

x2 = 5    y2 = 7

m = (y2 - y1)/(x2 - x1)

- Substitution

  m = (7 - 3)/(5 - 2)

- Slope

  m = 4/3

2.- Find the equation of the line

     y - y1 = m(x - x1)

     y - 3 = 4/3(x - 2)

     y - 3 = 4/3x - 8/3

     y = 4/3x - 8/3 + 3

     y = 4/3x - 8/3 + 9/3

     y = 4/3x + 1/3

8 0
3 years ago
Write an equation for the line parallel to y = -7x + 15 that passes through the point P(9,-6).
Elan Coil [88]

Answer:

y = -7x + 57

Step-by-step explanation:

If the line is parallel, it will have the same slope. So, this line will also have a slope of -7.

Use y = mx + b, plug in the slope and given point, and solve for b:

y = mx + b

-6 = -7(9) + b

-6 = -63 + b

57 = b

Plug in the slope and y intercept into y = mx + b:

y = mx + b

y = -7x + 57

So, the equation is y = -7x + 57

6 0
3 years ago
A conclusion drawn based on evidence from the story is:
Andre45 [30]

Answer:

textual evidence

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Complete 6,7 for 5 points.
seraphim [82]

Answer:

idk the answer

Step-by-step explanation:

4 0
3 years ago
2x + y - z = -8
Andreyy89

Answer:

Multiply row 1 by \frac{1}{2}.

Step-by-step explanation:

The augmented matrix of the system of linear equation is described below:

\left[\begin{array}{cccc}2&1&-1&-8\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]

Where a_{11} = 2, if we need to create a_{11} = 1, we need to multiply row 1 by \frac{1}{2}, that is to say:

\left[\begin{array}{cccc}1&\frac{1}{2} &-\frac{1}{2} &-4\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]

Hence, the correct answer is: Multiply row 1 by \frac{1}{2}.

5 0
3 years ago
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