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IrinaK [193]
3 years ago
5

The number of airline passengers in 1990 was 466 million. The number of passengers traveling by airplane each year has increased

exponentially according to the model, P ( t ) = 466 ⋅ 1.035 t , where t t is the number of years since 1990. In what year is it predicted that 900 million passengers will travel by airline?
Mathematics
1 answer:
taurus [48]3 years ago
6 0

Answer:

2010.

Step-by-step explanation:

We have been given an exponential growth formula P(t)=466\cdot 1.035^t, which represents number of passengers traveling by airplane since 1990.

To find the year in which 900 million passengers will travel by airline, we will equate the given formula by 900 and solve for t as:

900=466\cdot 1.035^t

\frac{900}{466}=\frac{466\cdot 1.035^t}{466}1.9313304721030043=1.035^t

Take natural log of both sides:

\text{ln}(1.9313304721030043)=\text{ln}(1.035^t)

Using property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

\text{ln}(1.9313304721030043)=t\cdot \text{ln}(1.035)

0.658209129198=t\cdot 0.034401426717

\frac{0.658209129198}{0.034401426717}=\frac{t\cdot 0.034401426717}{0.034401426717}

19.1331927775=t\\\\t=19.1331927775

This means that in the 20th year since 1990, 900 million passengers would travel by airline.

1990+20=2010

Therefore, 900 million passengers would travel by airline in 2010.

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400 Suppose a particular surveillance system has a 99% chance of correctly identifying a future terrorist and a 99.8% chance of
alexgriva [62]

Answer:

1.236 × 10^(-3)

Step-by-step explanation:

Let A be the event that the person is a future terrorist

Let B the event that the person is identified as a terrorist

We are told that there are 1,000 future terrorists in a population of 400 million. Thus, the Probability that the person is a terrorist is;

P(A) = 1000/400000000

P(A) = 0.0000025

P(A') = 1 - P(A)

P(A') = 1 - 0.0000025

P(A') = 0.9999975

We are told that the system has a 99% chance of correctly identifying a future terrorist. Thus; P(B|A) = 0.99

Thus, P(B'|A) = 1 - P(B|A)

P(B'|A) = 1 - 0.99

P(B'|A) = 0.01

We are told that there is a 99.8% chance of correctly identifying someone who is not a future terrorist. Thus; P(B'|A') = 0.998

Hence: P(B|A') = 1 - P(B'|A')

P(B|A') = 1 - 0.998

P(B|A') = 0.002

We want to find the probability that someone who is identified as a terrorist, is actually a future terrorist. This is represented by: P(A|B)

We can find it from bayes theorem as follows;

P(A|B) = [P(B|A) × P(A)]/[(P(B|A) × P(A)) + (P(B|A') × P(A')]

Plugging in the relevant values;

P(A|B) = [0.99 × 0.0000025]/[(0.99 × 0.0000025) + (0.002 × 0.9999975)]

P(A|B) = 0.00123597357 = 1.236 × 10^(-3)

8 0
3 years ago
H(t)=(t+3)^2+5
sineoko [7]

Answer:

Option C. −4≤t≤−3

Step-by-step explanation:

we have

H(t)=(t+3)^2+5

This is the equation of a vertical parabola written in vertex form

The parabola open upward (the leading coefficient is positive)

The vertex is a minimum

The vertex is the point (-3,5)

The function is increasing in the interval [-3,∞)

The function is decreasing in the interval (-∞,-3]

The function will have a negative average rate when the function will be decreasing

therefore

the answer is option C

7 0
3 years ago
Select the correct answer.
Marat540 [252]
I just did it it’s 212
5 0
3 years ago
Mary's weight went from 80kg to 68kg. express her weight loss as a % of her original weight
Ratling [72]

80-68=12

12/80=0.12


12% is the answer

6 0
3 years ago
Willy Wonka has 2 candies, Wonka bars and Everlasting Gobstoppers. Both have both natural sugar and sucrose in them. Each Wonka
love history [14]

Answer:

Wonka bars=3 and  Everlasting Gobstoppers=24

Step-by-step explanation:

let the wonka bars be X

and everlasting gobstoppers be Y

the objective is to

maximize 1.3x+3.2y=P

subject to constraints

natural sugar

4x+2y=60------1

sucrose

x+3y=75---------2

x>0, y>0

solving 1 and 2 simultaneously we have

4x+2y=60----1

x+3y=75------2

multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have

 4x+2y=60

 4x+12y=300

-0-10y=-240

10y=240

y=240/10

y=24

put y=24 in equation 2 we have'

x+3y=75

x+3(24)=75

x+72=75

x=75-72

x=3

put x=3 and y=24 in the objective function we have

maximize 1.3x+3.2y=P

1.3(3)+3.2(24)=P

3.9+76.8=P

80.7=P

P=$80.9

8 0
3 years ago
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