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VLD [36.1K]
2 years ago
14

1. Write the word sentence as an equation. 2. Then solve the equation. 5/7a=25

Mathematics
1 answer:
seropon [69]2 years ago
7 0

Answer:

a = 35

Step-by-step explanation:

5/7a = 25

multiply both sides by 7:

5a = 175

divide by 5:

a = 35

Hope this helps !!!

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I don't get thissssssssssssssssss
andrew11 [14]

Answer:

west wing ,north wing, east wing and south wing

Step-by-step explanation:

west wing = 5 4/11 =59/11 =5.3636...

north wing = 37/7 =5.25...

east wing = 5.21

south wing = 5.125

8 0
2 years ago
We learned in Exercise 4.18 that about 90% of American adults had chickenpox before adulthood. We now consider a random sample o
liraira [26]

Answer:

a) 108 people with a standard deviation of 3.286335

b) No

c) 0.218163 or around 21.82%

d) See explanation below.

Step-by-step explanation:

This situation can be modeled with the Binomial Distribution which gives t<em>he probability of an event that occurs exactly k times out of n, and is given by </em>

<em>\large P(k;n)=\binom{n}{k}p^kq^{n-k} </em>

<em>where  </em>

<em>\large \binom{n}{k}= combination of n elements taken k at a time. </em>

<em>p = probability that the event (“success”) occurs once </em>

<em>q = 1-p </em>

In this case, the event “success” is finding an American adult who had  chickenpox before adulthood with probability p=0.9

and n=120 American adults in the sample.

The <em>standard deviation for this binomial distribution</em> is

\large s=\sqrt{npq}

where <em>n is the sample size 120 </em>

a)

We consider a random sample of 120 American adults. How many people in this sample would you expect to have had chickenpox in their childhood?

If about 90% of American adults had chickenpox before adulthood, we expect to find 90% of 120 = 0.9*120=108 people in the sample who had chickenpox in their childhood.

The  standard deviation would be

\large s=\sqrt{120*0.9*0.1=3.286335}

b)

Would you be surprised if there were 105 people who have had chickenpox in their childhood?

No, because 105 and 108 are in the interval [mean - s, mean +s]

c)

What is the probability that 105 or fewer people in this sample have had chickenpox in their childhood?

The probability that 105 or fewer people in this sample have had chickenpox in their childhood is

\large \sum_{k=0}^{105}\binom{120}{k}0.9^k0.1^{120-k}

We compute this value easily with a spreadsheet and we get

\large \sum_{k=0}^{105}\binom{120}{k}0.9^k0.1^{120-k}=0.218163\approx 21.82\%

d)

How does this probability relate to your answer to part (b)?

A binomial distribution with np>5 and nq>5 with n the sample size as is the case here, behaves pretty much like a Normal distribution with mean np and standard deviation \large \sqrt{npq}, so around 60% of the data are in the interval  [mean -s, mean +s] and 40% outside, so roughly <em>20% of the data should be in [0, mean-s] </em>

4 0
3 years ago
HELP WILL MARK BRAINLIEST <br> If the sin 60° is
uranmaximum [27]
The answer is the 3rd option


30-60-90 triangle for reference

Remember soh cah toa

O:opposite, a:adjacent, h:hypotenuse

S:sin c:cosine t:tangent

Hope this helped :)
4 0
2 years ago
Read 2 more answers
2. What equation does the model below<br> represent?<br> -<br> -
Novay_Z [31]

Answer:

minus

Step-by-step explanation:

it means minus maybe think that what it means

6 0
3 years ago
Read 2 more answers
Which number is 5.389 rounded to the nearest hundredth? A 5.4 B 5.38 © 5.39 05.399
ankoles [38]

Answer:

c) 5.39

Step-by-step explanation:

The digit that is in the hundredths place is the 8. (The hundredths are two digits to the right of the point).

The thousandths in this case would be the 9, since the 9 is close to the next hundredth, the nearest hundredth would be 9 (adding 1 to the 8), therefore the number would be 5.39

7 0
3 years ago
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