All categories

3 years ago

There are 400 silver dollars in two bags. If 275 are in one bag, how many are in the other bag?

2 answers:

4 0

If there are 400 silver dollars in all, and there are 275 in one bag, to find the amount in the other bag, just subtract:

400-275=125

There are 125 in the other bag.

Alex73 [517]3 years ago

4 0

Well 400-275=125 so your answer would be 125 in the other bag

You might be interested in

Which number is 7.323 rounded to the nearest tenth? A 7.3 6 74 © 7.32 07.33

Kamila [148]

Answer:

Option A - 7.3.

Step-by-step explanation:

Given : Number 7.323.

To find : Which number is 7.323 rounded to the nearest tenth?

Solution :

Rounded to the nearest tenth rule :

1) If the hundredths place of a decimal is greater than or equal to five, then tenth place number is added by 1.

2) If the hundredths place of a decimal is less than five, then tenth place number does not change.

In the number 7.323

The Hundredth number is 2 < 5 so tenth number does not change.

7.323 rounded to the nearest tenth is 7.3.

Therefore, Option A is correct.

4 0

3 years ago

Will give brainliest Of the following sets, which numbers in {1, 2, 3, 4, 5} make the inequality 5x + 2 > 12 true? (5 points)

Radda [10]

Answer:

x = 3, 4, 5

Step-by-step explanation:

Solving the inequality

5x + 2 > 12 ( subtract 2 from both sides )

5x > 10 ( divide both sides by 5 )

x > 2

Thus the only values from the given set which make the inequality true are

x = 3, 4, 5

4 0

3 years ago

Read 2 more answers

The pound has three kinds of dogs: pit bull, chihuahuas and mutts. All but 23 of the dogs are pit bull, all but 17 are chihuahua

Georgia [21]

Answer:

There are 68 dogs in the pound.

Step-by-step explanation:

Number of pit bull dogs in a pound = P = 23

Number of chihuahuas dogs in a pound = C = 17

Number of mutts dogs in a pound = M = 28

Total number of dogs in a pound = T

$T = P+C+M=23+17+28=68$

There are 68 dogs in the pound.

5 0

3 years ago

A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken

kotegsom [21]

Answer: 68

Step-by-step explanation:

Formula for sample size when prior estimate of population proportion (p) is available: $n=p(1-p)(\dfrac{z^*}{E})^2$

, where z*= critical-value.

E= Margin of error.

Let p be the population proportion of trees are infected with the citrus red mite.

As per given , we have

$p=\dfrac{1}{5}=0.2$

E= ± 0.08

The critical z-value corresponding to 90% confidence level = z*=1.645

Substitute all the values in the above formula , we get

Required sample size : $n=(0.2)(1-0.2)(\dfrac{(1.645)}{0.08})^2$

$\Rightarrow\ n=(0.2)(0.8)(20.5625)^2$

$\Rightarrow\ n=0.16(422.81640625)\\\\\Rightarrow\ n=67.650625\approx68$ [Rounded to next integer.]

Thus, the minimum sample size should be taken =68

6 0

3 years ago

What is the answer key to GO MATH 6grade page 393

Lina20 [59]

Answer:

This website is not an answer key website. You ask a question and we respond. Write your question and ill reply. Thanks for the points.

Step-by-step explanation:

7 0

4 years ago