Answer:
219
Step-by-step explanation:
The figure has the shape of a trapezoid. We find the area of the trapezoid and subtract the area of the rectangular door.
area of trapezoid = (base1 + base2)h/2
area of trapezoid = (20 ft + 12 ft) * 15 ft / 2
area of trapezoid = 32 ft * 15 ft /2
area of trapezoid = 240 ft^2
area of rectangle = length * width
area of rectangle = 7 ft * 3 ft
area of rectangle = 21 ft^2
area to be painted = area of trapezoid - area of rectangle
area to be painted = 240 ft^2 - 21 ft^2
area to be painted = 219 ft^2
Answer: 219 ft^2
60/96 = 0.625 , times that by 100 gives you the percentage of 62.5%
A) The longest horizontal distance is reached at 45 degrees angle. This is true for any projectile launch.
B) First, calculate fligth time (using the vertical motion) and then calculate the horizontal movement.
Flight time = 2* ascendent time
ascendent time => final vertical velocity, Vy, = 0
sin(45) = Voy / Vo => Voy = Vosin(45) = 25.5 m/s * (√2) / 2 = 18.03 m/s
Vy = Voy - gt = 0 => Voy = gt = t = Voy / g
Use g = 10 m/s^ (it is an aproximation, because the actual value is about 9.81 m/s^2 depending on the latitud)
t = 18.03 m/s / 10 m/s^2 = 1.83 s
This is the ascendant time going upward.
The flight time is 2*1.83 = 3.66 s
Horizontal motion
Horizontal velocity = Vx = constant = Vox = Vo*cos(45) = 18.03 m/s
Vx = x / t => x = Vx*t
Horizontal distance = xmax = 18.03m/s*3.66 s = 65.99 m
c) The time the ballon will be in the air was calculated in the part B, it is 18.03 s
